3 years ago

Please i need help:/

Mathematics

1 answer:

Anestetic [448]3 years ago

3 0

Answer:

its not letting me see the picture

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In a sale, all prices are reduced by 25%. Work out the

Leno4ka [110]

Answer:

1650

Step-by-step explanation:

2200*.25=1650 sale price

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3 years ago

Simon says "five time my age 4 years ago is the same as three time my age in 2 years" how old is simon

omeli [17]

Simon is 13 years old

Let x be Simon's age

Thus 4 years ago his age was (x - 4) and 2 years from now his age is (x + 2)

Hence 5(x - 4) = 3(x + 2)

distributing both sides gives

5x-20 = 3x + 6

subtract 3x from both sides of the equation

5x - 3x - 20 = 6

2x - 20 = 6

add 20 to both sides

2x = 6 + 20 = 26

divide both sides by 2

x = $\frac{26}{2}$ = 13

Simon is 13 years old

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3 years ago

The volume of Cube A is 100 cm3. What is the volume of Cube B given they are similar?

valkas [14]

Answer:

50cm

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3 years ago

The Pythagorean theorem is true for all similar triangles.<br> A. True<br> B. False

Afina-wow [57]

False. It only relates to the sides of a right triangle in a simple way, so that if the lengths of any two sides are known, the length of the third side can be found.

5 0

3 years ago

Read 2 more answers

The angle θ1\theta_1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end

melomori [17]

Answer:

$\dfrac{3\sqrt{13}}{11}$

Step-by-step explanation:

Given that the angle $\theta_1$ is located in Quadrant II; and

$\cos(\theta_1)=-\dfrac{2}{11}$

In Quadrant II, x is negative and y is positive.

$\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\$

To find $\sin(\theta_1)$ , we first determine the opposite angle of $\theta_1$ .

This will be done using the Pythagoras theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}$

Therefore:

$\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}$

6 0

3 years ago