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Sunny_sXe [5.5K]
2 years ago
8

Please i need help:/

Mathematics
1 answer:
Anestetic [448]2 years ago
3 0

Answer:

its not letting me see the picture

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How do I verify #15 using fundamental trig identities?
expeople1 [14]

We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

\frac{sin \theta + tan \theta}{1+cos \theta}

Using Quotient identity for tangent function, we will get

\frac{sin \theta+ \frac{sin \theta}{cos \theta}}{1+cos \theta}

\frac{sin \theta cos \theta + sin \theta}{cos \theta(1+cos \theta)}

Taking out sine function from the numerator

=\frac{sin \theta(1+cos \theta)}{cos \theta(1+cos \theta)}

Cancelling the common term of numerator and denominator

=\frac{sin \theta}{cos \theta} = tan \theta

7 0
3 years ago
Show how to rewrite 1/5 with the denominator 10.
Gnoma [55]

Answer:

first blank: 2

second blank: 2

8 0
3 years ago
Suppose angles A and B are complementary angles and m∠A = (x-5)° and m∠B = (2x+20)° Solve for X and then find m∠A and m∠B
MariettaO [177]

The angles are x =25, angle A = 20 and B = 70

<h3>How to solve for the angles?</h3>

The given parameters are:

A = x - 5

B = 2x + 20

Both angles are complementary angles.

This means that:

x - 5 + 2x + 20 = 90

Evaluate the like terms

3x = 75

Divide both sides by 3

x = 25

Substitute x = 25 in A = x - 5 and B = 2x + 20

A = 25 - 5 = 20

B = 2 * 25 + 20 = 70

Hence, the angles are x =25, angle A = 20 and B = 70

Read more about complementary angles at:

brainly.com/question/98924

#SPJ1

3 0
2 years ago
Geometry !!! Pls help it’s timed!!
DENIUS [597]

Answer:

the answer is the first choice .

6 0
2 years ago
PLEASE HELP!! If the endpoints of have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of ?
dimaraw [331]

M refers to midpoint.

A(9, 8) \\B(-1, -2) \\M(\frac{x_1-x_2}{2}, \frac{y_1-y_2}{2}) \\M(\frac{9-(-1)}{2}, \frac{8-(-2)}{2}) \\M(\frac{10}{2}, \frac{10}{2})\Longrightarrow\boxed{M(5, 5)}

Hope this helps.

r3t40

6 0
3 years ago
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