Find the product of 3a+5 and 2a^(2)+4a-2

1 answer:

6 0

The answer is 6a3+22a2+14a−10
My steps:
(3a+5)(2a^2+4a−2)=(3a+5)(2a^2+4a+−2)=(3a)(2a^2)+(3a)(4a)+(3a)(−2)+(5)(2a^2)+(5)(4a)+(5)(−2)=6a^3+12a^2−6a+10a^2+20a−10=6a^3+22a^2+14a−10

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