Find the product of 3a+5 and 2a^(2)+4a-2

1 answer:

6 0

The answer is 6a3+22a2+14a−10
My steps:
(3a+5)(2a^2+4a−2)=(3a+5)(2a^2+4a+−2)=(3a)(2a^2)+(3a)(4a)+(3a)(−2)+(5)(2a^2)+(5)(4a)+(5)(−2)=6a^3+12a^2−6a+10a^2+20a−10=6a^3+22a^2+14a−10

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jek_recluse [69]

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3 years ago

Solve for x. 2(2-x) + 12x =44

Nataly [62]

Answer:

2(2-x)+12x=44

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-4 -4

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10x=40

/10 /10

x=4

Step-by-step explanation:

first you multiply the (2-x) by 2, you then subtract the 4 from both sides of the equation, you end up with -2x +12x = 40. Then subtract the 2x from the 12x and you end up with 10x. so now 10x=40. You then divide both sides by 10 and end up with x=10

sorry im not to good at explaining haha

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Vlad1618 [11]

I think y =2041 hope this helps

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3 years ago