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3 years ago

7

Find the product of 3a+5 and 2a^(2)+4a-2

1 answer:

Ilia_Sergeevich [38]3 years ago

6 0

The answer is <span><span><span>6<span>a3</span></span>+<span>22<span>a2</span></span></span>+<span>14a</span></span>−<span>10
My steps:
</span><span><span>(<span><span>3a</span>+5</span>)</span><span>(<span><span><span>2<span>a^2</span></span>+<span>4a</span></span>−2</span>)</span></span><span>=<span><span>(<span><span>3a</span>+5</span>)</span><span>(<span><span><span>2<span>a^2</span></span>+<span>4a</span></span>+<span>−2</span></span>)</span></span></span><span>=<span><span><span><span><span><span><span>(<span>3a</span>)</span><span>(<span>2<span>a^2</span></span>)</span></span>+<span><span>(<span>3a</span>)</span><span>(<span>4a</span>)</span></span></span>+<span><span>(<span>3a</span>)</span><span>(<span>−2</span>)</span></span></span>+<span><span>(5)</span><span>(<span>2<span>a^2</span></span>)</span></span></span>+<span><span>(5)</span><span>(<span>4a</span>)</span></span></span>+<span><span>(5)</span><span>(<span>−2</span>)</span></span></span></span><span>=<span><span><span><span><span><span>6<span>a^3</span></span>+<span>12<span>a^2</span></span></span>−<span>6a</span></span>+<span>10<span>a^2</span></span></span>+<span>20a</span></span>−10</span></span><span>=<span><span><span><span>6<span>a^3</span></span>+<span>22<span>a^2</span></span></span>+<span>14a</span></span>−<span>10</span></span></span>

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