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3 years ago

Find the product of 3a+5 and 2a^(2)+4a-2

1 answer:

6 0

The answer is 6a3+22a2+14a−10
My steps:
(3a+5)(2a^2+4a−2)=(3a+5)(2a^2+4a+−2)=(3a)(2a^2)+(3a)(4a)+(3a)(−2)+(5)(2a^2)+(5)(4a)+(5)(−2)=6a^3+12a^2−6a+10a^2+20a−10=6a^3+22a^2+14a−10

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Nicole runs 7 miles in 50 minutes. At the same rate, how many miles would she run in 75 minutes?

nikdorinn [45]

Answer:10.5 ml

Step-by-step explanation:do 75/50=1.5

Do 7 times 2.6 and get 7+2.5=10.5 miles

4 0

2 years ago

Please helppppp pls it's in the screenshot

sergey [27]

Answer:

4. 11/6, 121/36

5. 5/8, 25/64

6. 4/7, 16/49

7. 14/9, 196/81

Step-by-step explanation:

The ratio of perimeters is the same as the ratio of corresponding legs:

perimeter ratio = red leg/blue leg

The area ratio is the square of that:

area ratio = (perimeter ratio)²

perimeter ratio = 11/6

area ratio = (11/6)² = 121/36

perimeter ratio = 5/8

area ratio = (5/8)² = 25/64

perimeter ratio = 4/7

area ratio = (4/7)² = 16/49

perimeter ratio = 14/9

area ratio = (14/9)² = 196/81

3 0

2 years ago

How to divide 453 by 8 in standard form

Leno4ka [110]

Answer:

56 5/8

Step-by-step explanation:

453/8

8 0

3 years ago

20 people show up to the party, and Robert decides to give them each the same

nadya68 [22]

Answer:

depends on how much pizza he has.

Step-by-step explanation:

8 0

2 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago