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2 years ago

Help me please! :Will give brainliest!:

Mathematics

2 answers:

Harlamova29_29 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

Anything that is multiplied greater than 1 will be greater than what the other factor is. You are correct!

Artemon [7]2 years ago

3 0

Answer:

B, 2 5/6 x 2 5/6

Step-by-step explanation:

This is the only answer that is greater than 2 5/6

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Solve for q. -5(3-q) +4=5q-11

soldier1979 [14.2K]

Perform the indicated multiplication first: -15 + 5q + 4 = 5q - 11

Note that 5q appears on both sides of this equation. Cancelling, we get :

-11 = -11. This is always true. Thus, -5(3-q) +4=5q-11 is true for all q.

4 0

2 years ago

#11-16 please 15 points

Serjik [45]

11. Similar 1/2
12. Similar 2
13. no
14. no
15. No, they are not congruent because rectangles do not have equal sides, so the length of one triangle could be longer than the other and the width ozone can be shorter than the other.
16. Yes

3 0

2 years ago

Can anybody explain how to subtract mixed fractions?

Ilya [14]

Answer:

<em>convert </em>the mixed fractions to improper fractions (where the numerator is greater than or equal to the denominator): multiply the whole number part by the fraction's denominator, add that to the numerator, write the result on top of the denominator.
if the denominators are not the same, work out the common denominator and <em>rewrite </em>the fractions with the same denominators
subtract by subtracting the numerators and writing the result over the denominator
convert back to mixed fractions by dividing the numerator by the denominator, write down the whole number answer, write down the remainder above the denominator.

Example

$3\frac23-1\frac45$

convert to improper fractions:

$\dfrac{3 \times 3+2}{3}-\dfrac{1 \times 5+4}{5}=\dfrac{11}{3}-\dfrac{9}{5}$

common denominator = 3 × 5 = 15, so:

$\dfrac{11}{3}-\dfrac{9}{5}=\dfrac{11\times 5}{3\times 5}-\dfrac{9\times 3}{5\times 3}=\dfrac{55}{15}-\dfrac{27}{15}$

subtract:

$\dfrac{55}{15}-\dfrac{27}{15}=\dfrac{55-27}{15}=\dfrac{28}{15}$

convert back to mixed fractions:

$28 \div 15=1 \textsf{ remainder }13=1 \frac{13}{15}$

7 0

2 years ago

Read 2 more answers

Determine whether the series is convergent or divergent. [infinity] n = 1 1 n√9 the series is a ---select--- p-series with p =

inna [77]

The series is a convergent p-series with p = 3

<h3>How to know it is a divergent or a convergent series</h3>

We would know that a series is a convergent p series when we have ∑ 1 np. Then you have to be able to tell if the series is a divergent p series or it is a convergent p series.

The way that you are able to tell this is if the terms of the series do not approach towards 0. Now when the value of p is greater than 1 then you would be able to tell that the series is a convergent series.

The value of $\sqrt{9}= 3$

The formular for this is

∑ $\frac{1}{n^p} \\$

where n = 1

we know it is convergent because p is greater than 1. 3>1