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Nadusha1986 [10]
2 years ago
7

Rhonda took $20 with her to spend on popcorn and candy for herself and her friends at the movie theater. The price for each bag

of popcorn was $5. The price of each box of candy was half the price of a bag of popcorn.
Use one axis to represent the number of bags of popcorn and the other axis to represent the number of boxes of candy. Create an equation and sketch the graph that represents the number of each item she can purchase. Be sure to clearly label the intercepts.
In words, explain your graph and what the intercepts mean in context of the situation.

Mathematics
1 answer:
MrRa [10]2 years ago
5 0

The linear equation that represents the scenario is 5x + 2.5y = 20

<h3>How to determine the equation?</h3>

The given parameters are:

  • Popcorn = $5 per bag
  • Candy = $2.5 per bag i.e. half the price of pop corn

Let x represents popcorn and y represents candy.

So, we have:

5x + 2.5y = 20

The intercepts in this case are the maximum number of candy and popcorn Rhonda can buy

See attachment for the graph

Read more about linear functions at:

brainly.com/question/4025726

#SPJ1

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Answer:

B- $38.00

Step-by-step explanation:

Since there are two adults, you would multiply the cost of adults by number of adults. in this case that would be $10.75 x 2= $21.50. do the same for the kids and you will get $5.50 x 3 = $16.50. add 16.50 and 21.50 and you will get $38.00 which is your answer

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7

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"La suma de la medida de los ángulos interiores de cualquier triángulo, es igual a dos triángulos rectos, o sea a 180°."
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Efectivamente, la suma de la medida de los ángulos internos de cualquier figura triangular es igual a 180º. Ahora bien, la oración posee un error de redacción, pues tanto los triángulos rectos como los equiláteros o los isósceles poseen dicha característica, es decir, no es únicamente una característica de los triángulos rectos. Además, la suma de los ángulos interiores de dos triángulos rectos sería igual a 360º, no a 180º.  

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nata0808 [166]

Answer:

−35.713332 ; 0.313332

Step-by-step explanation:

Given that:

Sample size, n1 = 11

Sample mean, x1 = 79

Standard deviation, s1 = 18.25

Sample size, n2 = 18

Sample mean, x2 = 96.70

Standard deviation, s2 = 20.25

df = n1 + n2 - 2 ; 11 + 18 - 2 = 27

Tcritical = T0.01, 27 = 2.473

S = sqrt[(s1²/n1) + (s2²/n2)]

S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]

S = 7.284

(μ1 - μ2) = (x1 - x2) ± Tcritical * S

(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284

(μ1 - μ2) = - 17.7 ± 18.013332

-17.7 - 18.013332 ; - 17.7 + 18.013332

−35.713332 ; 0.313332

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