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Nadusha1986 [10]
2 years ago
7

Rhonda took $20 with her to spend on popcorn and candy for herself and her friends at the movie theater. The price for each bag

of popcorn was $5. The price of each box of candy was half the price of a bag of popcorn.
Use one axis to represent the number of bags of popcorn and the other axis to represent the number of boxes of candy. Create an equation and sketch the graph that represents the number of each item she can purchase. Be sure to clearly label the intercepts.
In words, explain your graph and what the intercepts mean in context of the situation.

Mathematics
1 answer:
MrRa [10]2 years ago
5 0

The linear equation that represents the scenario is 5x + 2.5y = 20

<h3>How to determine the equation?</h3>

The given parameters are:

  • Popcorn = $5 per bag
  • Candy = $2.5 per bag i.e. half the price of pop corn

Let x represents popcorn and y represents candy.

So, we have:

5x + 2.5y = 20

The intercepts in this case are the maximum number of candy and popcorn Rhonda can buy

See attachment for the graph

Read more about linear functions at:

brainly.com/question/4025726

#SPJ1

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3 years ago
A sample of lake water contains 150grams of salt. If 30% of the water sample is salt, find the number of grams the entire sample
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Answer:

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Step-by-step explanation:

Let's say that the total number of grams of the sample is x. We know that 30% of x is salt and we also know this quantity is 150 grams. So, we can write this as:

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Remember that % is simply "out of 100", so 30% = 30/100 = 0.30. Then:

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Hope this helps!

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3 years ago
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Answer:

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Step-by-step explanation:

Subtract 18 from behind the equal sign to cancel it out. This leaves you with 2(p+1)- 18= 0.

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This would leave you with 2= 0, but that's not true so continue on to the variable.

So p - 8= 0 making the answer p = 8

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Step-by-step explanation:

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2 years ago
what is the distance between point (-5, -2) and point (8, -3) rounded to the nearest tenth? will appreciate all the help
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\text {Distance =}  \sqrt{((Y_2-Y_1)^2+(X_2-X_1)^2}

\text {Distance =}  \sqrt{((-3-(-1))^2+(8-(-5))^2}

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\text {Distance =} 13.0 \text { units}
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