V1 - velocity first train
v2 - velocity second train
v2 > v1
v2 - v1 = 17 mph
We know, that:
![s_1+s_2=210 \ [miles] \\ \\ t_1=t_2=2h](https://tex.z-dn.net/?f=s_1%2Bs_2%3D210%20%5C%20%5Bmiles%5D%20%5C%5C%20%5C%5C%20t_1%3Dt_2%3D2h)
So:
NOw we've got simple system of equations:
![+\begin{cases} v_2-v_1=17 \\ v_2+v_1=105\end{cases} \\ \\ 2v_2=122 \qquad /:2 \\ \\ v_2=61 \qquad [mph] \\ \\ v_2-v_1=17 \\ \\ 61-v_1=17 \\ \\ v_1=44](https://tex.z-dn.net/?f=%2B%5Cbegin%7Bcases%7D%20v_2-v_1%3D17%20%5C%5C%20v_2%2Bv_1%3D105%5Cend%7Bcases%7D%20%5C%5C%20%5C%5C%202v_2%3D122%20%5Cqquad%20%2F%3A2%20%5C%5C%20%5C%5C%20v_2%3D61%20%5Cqquad%20%5Bmph%5D%20%5C%5C%20%5C%5C%20v_2-v_1%3D17%20%5C%5C%20%5C%5C%2061-v_1%3D17%20%5C%5C%20%5C%5C%20v_1%3D44)
Velocities of these trains are 61mph and 44mph
total of ages now is 67 + 4 + 4 = 75
S=shelly
M= Michelle
Michelle is 3 yrs younger than Shelly so use S-3
S +M = 75
replace M with S-3 to get:
S +S-3=75
2S=78
s=39
So shelly is 39
Michelle is 3 years younger = 39-3 = 36
Answer:
y = x +3
Step-by-step explanation:
When you examine the table, you see that each y-value is 3 more than the corresponding x-value. This is represented in the equation ...
y = x +3
Yes it is. log(1) and ln(1) both equal zero. But you cannot take the logarithm of 0.
Answer: ΔKE = 760.5 Joules
Step-by-step explanation:
Isnt the formula for ΔKE = 0.5m*v^2???
Im not going to use that formula you gave me, its wrong.
900/2 = 450
1.3^2 = 1.69
450 x 1.69 = 760.5 Jules
This is also the wrong subject btw
