Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
Answer
Red is 6
Orange is 4
Purple is 3
Green and Turquoise are both 2
Step-by-step explanation:
Hope this was helpful!!
ANSWER
![-\frac{\sqrt[]{3}}{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D)
EXPLANATION
Given
We can find cos 150 by using
recall that
![\begin{gathered} \cos 30=\frac{\sqrt[]{3}}{2} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%2030%3D%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Hence,
![\begin{gathered} \cos 150=-\cos 30 \\ =-\frac{\sqrt[]{3}}{2} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%20150%3D-%5Ccos%2030%20%5C%5C%20%3D-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Therefore, the value of cos 150 is
The answer is one you don’t use the x and 2-1=1
Should be 2 as this makes the numbers positive and the action of subtraction doesn't change
