Graph the line that represents the equation Y+2= 1/2(x+2)

Mathematics

1 answer:

zmey [24]2 years ago

6 0

Answer:

Dear user,

Answer to your query is provided in image attached

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What is the force of gravity (in Newtons) acting between the Earth and a 100-kg person who is on board the International Space S

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Answer:

$f_{G}=317877.55 N = 317.8 kN$

Step-by-step explanation:

$f_{G}= (G*m_{1}*m_{2})/r^{2} \\Where:\\f_{G}= force of gravity\\G=gravitational constant= 6.6x10^{-11}m^{3}kg^{-1}s^{-2}\\ m_{1}= earth mass = 5.9x10^{24}kg\\m_{2}=person mass = 100kg\\r= distance between the bodies=350km= 350 000 m$

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Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!