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2 years ago

Graph the line that represents the equation Y+2= 1/2(x+2)

Mathematics

1 answer:

zmey [24]2 years ago

6 0

Answer:

Dear user,

Answer to your query is provided in image attached

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Without graphing, write the equation of the axis of symmetry for f(x) = 4|x + 8] - 5.

iren [92.7K]

Answer:

The line of symmetry is x=8

Step-by-step explanation:

7 0

2 years ago

One spring day, Landon noted the time of day and the temperature, in degrees Fahrenheit. His findings are as follows: At 6 a.m.,

Verizon [17]

Answer:

Graph these points listed below

Step-by-step explanation:

Graph the following points:

(6 am, 50)

(9 am, 59)

(1 pm, 63)

(6 pm, 63)

(8 pm, 59)

(12 am midnight, 58)

6 0

2 years ago

What's the range of 37000 and 45000

Galina-37 [17]

Range: Subtract 37000 from 45000 and you'll have it.

8 0

3 years ago

The amount of soft drink in a bottle is a Normal random variable. Suppose that in 7% of the bottles containing this soft drink t

WITCHER [35]

Answer:

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

7% of the bottles containing this soft drink there are less than 15.5 ounces

This means that when X = 15.5, Z has a pvalue of 0.07. So when X = 15.5, Z = -1.475.

$Z = \frac{X - \mu}{\sigma}$

$-1.475 = \frac{15.5 - \mu}{\sigma}$

$15.5 - \mu = -1.475\sigma$

$\mu = 15.5 + 1.475\sigma$

10% of them there are more than 16.3 ounces.

This means that when X = 16.3, Z has a pvalue of 1-0.1 = 0.9. So when X = 16.3, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{16.3 - \mu}{\sigma}$

$16.3 - \mu = 1.28\sigma$

$\mu = 16.3 – 1.28\sigma$

From above

$\mu = 15.5 + 1.475\sigma$

$15.5 + 1.475\sigma = 16.3 – 1.28\sigma$

$2.755\sigma = 0.8$

$\sigma = \frac{0.8}{2.755}$

$\sigma = 0.29$

The mean is

$\mu = 15.5 + 1.475\sigma = 15.5 + 1.475*0.29 = 15.93$

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

6 0

2 years ago

Limit as x approaches 0 of csc3x/cotx

jolli1 [7]

Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
csc(3x) / cot(x)
csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3

So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3

 $\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}$

6 0

3 years ago