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Zolol [24]
3 years ago
12

Fine the mean,median,mode and range for the followimg data set

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0
We need the actual data set to do anything
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What is the value of x?<br>​
HACTEHA [7]
12, because the triangle is a 45,45,90 so sides a and b are both x, and the hypotenuse is x times the square root of 2. this means the hypotenuse is 6• the square root of 2• the square root of 2, the square root of 4 is 2. 6•2=12
5 0
3 years ago
Read 2 more answers
What is the value of the function y=2x−3 when x=−1 ?
san4es73 [151]

Answer:  First option is correct.

Step-by-step explanation:

Since we have given that

y=2x-3

We need to find the value of the function .

As we have given that x= - 1

so, we substitute the value of x in y :

y=2x-3\\\\y=2(-1)-3\\\\y=-2-3\\\\y=-5

So, the value of the function is -5.

Hence, First option is correct.


7 0
4 years ago
Read 2 more answers
19. Find the least common multiple of x² + 4x +3 and x² + 7x + 12.
Tems11 [23]

Answer:

  C.  (x +1)(x +3)(x +4)

Step-by-step explanation:

The least common multiple is the product of the unique factors of each of the expressions. To find it, we need to factor each expression and identify the unique factors.

__

<h3>factorization</h3>

  x² +4x +3 = (x +3)(x +1)

  x² +7x +12 = (x +3)(x +4)

<h3>LCM</h3>

The unique factors are (x +1), (x +3), (x +4). The LCM is their product:

  LCM = (x +1)(x +3)(x +4)

_____

<em>Additional comment</em>

The positive sign of the constant (+3, +12) in each case tells you that the constants in the binomial factors will have the same sign. The positive sign of the linear term (+4x, +7x) in each case tells you the binomial factors will have constants with a positive sign. So, all of the answer choices that have negative constants can be eliminated.

3 0
2 years ago
Select the correct answer.
Degger [83]
Its D, no problem. Hope this helpedp

6 0
3 years ago
(y4 – y3 + 2y2 + y – 1) ÷ (y3 + 1)
Monica [59]
<span>a+b) • (a2-ab+b2)
</span><span>(a+b) • (a2-ab+b2) = 
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+<span>b<span>3
ANWSER </span></span></span><span> y4 - y3 + 2y2 + y - 1 —————————————————————— (y + 1) • (y2 - y + 1)</span>
5 0
3 years ago
Read 2 more answers
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