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Alekssandra [29.7K]
3 years ago
13

For f(x) = -3x + 8 , find f(x) when x = -2

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0
The answer is F=-7 plug in the -2 into the equation next Time
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A confidence interval for a population mean __________. A. Estimates a likely interval for a population mean B. Estimates likeli
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Answer:

<h3>Option A)  Estimates a likely interval for a population mean is correct</h3><h3>Hence a confidence interval for a population mean is used to  <u>Estimates a likely interval for a population mean</u></h3>

Step-by-step explanation:

Given that a confidence interval for a population mean  <u>Estimates a likely interval for a population mean</u>

For :

A confidence interval is a range of values that’s likely to include a population value with a certain degree of confidence.

It can be expressed as a the (percentage value) \% where by a population mean lies between an upper and lower interval.

Therefore a confidence interval for a population mean is used to  <u>Estimates a likely interval for a population mean</u>

Option A)  Estimates a likely interval for a population mean is correct

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4 years ago
What is 0.76 as a fraction is 79/100
blagie [28]

Answer:

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Step-by-step explanation:

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4 years ago
What is y-5=x in slope intercept form
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Y=x+5. add 5 to both sides
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3 years ago
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Past records indicate that the probability of online retail orders
Tcecarenko [31]

Answer:

a) Mean = 1.6, standard deviation = 1.21

b) 18.87% probability that zero online retail orders will turn out to be fraudulent.

c) 32.82% probability that one online retail order will turn out to be fraudulent.

d) 48.31% probability that two or more online retail orders will turn out to be fraudulent.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The mean of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that:

p = 0.08, n = 20

a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent?

Mean

E(X) = np = 20*0.08 = 1.6

Standard deviation

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.08*0.92} = 1.21

b. What is the probability that zero online retail orders will turn out to be fraudulent?

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.08)^{0}.(0.92)^{20} = 0.1887

18.87% probability that zero online retail orders will turn out to be fraudulent.

c. What is the probability that one online retail order will turn out to be fraudulent?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{20,1}.(0.08)^{1}.(0.92)^{19} = 0.3282

32.82% probability that one online retail order will turn out to be fraudulent.

d. What is the probability that two or more online retail orders will turn out to be fraudulent?

Either one or less is fraudulent, or two or more are. The sum of the probabilities of these events is decimal 1. So

P(X \leq 1) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

From itens b and c

P(X \leq 1) = 0.1887 + 0.3282 = 0.5169

P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.5169 = 0.4831

48.31% probability that two or more online retail orders will turn out to be fraudulent.

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Is the equation linear or quadratic?<br> t(x)=x+5<br> O A. linear<br> O B. quadratic
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Answer:

A. Linear

Step-by-step explanation:

The equation (t(x)=x+5) is a linear equation. As per its definition, a linear equation is an equation where all terms are to the first degree, meaning that none of the terms have an exponent. The equation, (t(x)=x+5) falls under this category, as none of its terms has an exponent, therefore, the equation is a linear equation.

4 0
3 years ago
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