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Aliun [14]
3 years ago
8

Help answer 1 and 2 pls

Mathematics
1 answer:
Serjik [45]3 years ago
5 0

Answer:

1. 0,4

2. x=-2

Step-by-step explanation:

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What is 4-2y+(-8y)+6.2 simplified
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 - 10 y+10.2

Step-by-step explanation:

4-2y+(-8y)+6.2

combine like terms

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-8*2x would be -16x and -8*-8=64 so the ansewer would be _16x+64

Step-by-step explanation:

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Given the equation f(x)=2x^2-14x+10, find g(x), the image of f(x) after a ry=x (reflection over the line y=x). Express your answ
Illusion [34]

Given:

The function is:

f(x)=2x^2-14x+10

The function g(x), the image of f(x) after a r_{y=x} (reflection over the line y=x).

To find:

The function g(x).

Solution:

We have,

f(x)=2x^2-14x+10

Substitute f(x)=y in the given function.

y=2x^2-14x+10

The function g(x), the image of f(x) after a r_{y=x} (reflection over the line y=x). So, interchange x and y.

x=2y^2-14y+10

Now, we need to find the value of y.

x=2(y^2-7y+5)

\dfrac{x}{2}=y^2-7y+5             [Divide both sides by 2]

\dfrac{x}{2}-5=y^2-7y             [Subtract 5 from both sides]

Add both sides half of square of coefficient of y, i.e. (\dfrac{-7}{2})^2, to make it perfect square.

\dfrac{x}{2}-5+(\dfrac{-7}{2})^2=y^2-7y+(\dfrac{-7}{2})^2

\dfrac{x}{2}-5+\dfrac{49}{4}=y^2-7y+(\dfrac{7}{2})^2

\dfrac{x}{2}-5+\dfrac{49}{4}=\left(y-\dfrac{7}{2}\right)^2          [\because (a-b)^2=a^2-2ab+b^2]

\dfrac{x}{2}+\dfrac{49-20}{4}=\left(y-\dfrac{7}{2}\right)^2

Taking square root on both sides, we get

\pm\sqrt{\dfrac{x}{2}+\dfrac{29}{4}}=y-\dfrac{7}{2}

\dfrac{7}{2}\pm\sqrt{\dfrac{2x+29}{4}}=y

\dfrac{7}{2}\pm\dfrac{\sqrt{2x+29}}{2}=y

\dfrac{7\pm \sqrt{2x+29}}{2}=y

Substituting y=g(x), we get

\dfrac{7\pm \sqrt{2x+29}}{2}=g(x)

Therefore, the required function is g(x)=\dfrac{7\pm \sqrt{2x+29}}{2}.

6 0
3 years ago
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