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aivan3 [116]
3 years ago
13

Ten people can dig 2 acres of land in 7 days. How long will 8 people working at half the rate of the first group take to dig 6 a

cres of piece of land?​
Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

Answer:

52.5 days

Step-by-step explanation:

Ten people can dig 2 acres in 7 days.

One person can dig 0.2 acres in 7 days.

Working at half the rate, one person can dig 0.1 acre in 7 days.

8 people can dig 0.8 acres in 7 days.

8 people can dig 6/0.8 * 0.8 acres in 6/0.8 * 7 days.

8 people can dig 6 acres in 52.5 days

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Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
V varies inversely with T and V=12 when T=6. Which equation shows this relationship
hodyreva [135]

Answer:

D

Step-by-step explanation:

Given V varies inversely as T, then the equation relating them is

V = \frac{k}{T} ← k is the constant of variation

To find k use the condition, V = 12 when T = 6

k = VT = 12 × 6 = 72

V = \frac{72}{T} ← equation of variation

5 0
3 years ago
A test has 10 true/false questions. How many different tests can be turned in to the teacher?
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The same as the greatest number that can be written
with 10 binary bits:  <u>1,024</u>
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3 years ago
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What was the depth of the submarine after 6 minutes
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