3 years ago

Find two numbers that have a greatest common factor of 13

Mathematics

2 answers:

777dan777 [17]3 years ago

6 0

1 and 20 I hope this helps

Ilia_Sergeevich [38]3 years ago

5 0

You can use 26 and 39

Hope this helps^-^

You might be interested in

Write the pair of fractions as a pair of fractions with a common denominator

Ostrovityanka [42]

3/10 and 4/10 and 4/12 and 9/12

7 0

3 years ago

What radian measure is equivalent to 900°?<br> 5n<br> 10n<br> 1/5n<br> 9n

Sergeu [11.5K]

9n is the answer to this question

3 0

3 years ago

Read 2 more answers

Find the sum of the first 90 terms of the sequence -4,-1,2,5,8

telo118 [61]

Answer:

1655

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence

d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3

This indicates the sequence is arithmetic with sum to n terms

$S_{n}$ = $\frac{n}{2}$ [ 2a₁ + (n - 1)d ]

Here a₁ = - 4, d = 3 and n = 90, thus

$S_{90}$ = $\frac{90}{2}$ [ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655

4 0

3 years ago

Please help I’m failing

vredina [299]

The answer is B.........

8 0

3 years ago

Read 2 more answers

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

4 years ago