Which of the following expressions are equivalent?
1 answer:
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Answer:
1.08 seconds
Step-by-step explanation:
given data
<u>first equation:</u>
According to the data, sharon position will be
h(t)= -16 + 4t +18---->eq(1)
<u>Second equation;</u>
When Sharon jumps, Megan throws a beach ball up to Sharon with an initial upward velocity of 16 ft/s from a height 5 feet off the ground to the nearest hundredth of a second
therefore, ball position would be
h(t)= -16 +16t +5 --->eq(2)
In order to find how long after she jumps does the ball reach Sharon i.e time, we will equate eq(1) and eq(2)
Therefore,
eq(1)= eq(2)
-16 +4t +18 = -16
+ 16t +5 --->(further simplifying it)
-16 + 16
+ 18 -5 = 16t - 4t
13 = 12t
t= 13/12
t= 1.08 s
Thus it took 1.08 seconds.