Answer:
Step-by-step explanation:
Step-by-step explanation:
T = time in seconds
H = distance
Tground = time to return to ground
Tmax = time at maximum height
H = -16T^2 + 672T...eqn 1
projectile returns to ground at H =0,
subs for H in eqn 1...
0 = -16T^2 + 672T
solving for T we get...
16T^2 = 672T
=> Tground = 42secs
Tmax = 0.5 Tground = 21secs
Answer:
Step-by-step exExplanation:
4
x
=
7
4
−
2
x
=
1
4
2
x
=
1
(
4
x
)
2
=
1
(
7
)
2
=
49
