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oksano4ka [1.4K]
3 years ago
8

What are the answers to these?

Mathematics
1 answer:
nordsb [41]3 years ago
8 0

Answer:

Step-by-step explanation:

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Complete the pattern.5,10,30,60,180,_____
gladu [14]

it would be 360 because it is just multiplying by 2, and then by 3, then back to 2

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Which law would you use to simplify the expression 3^10/3^4
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When dividing a term with the same constant but different exponents, use the quotient of power rule to simply the given expression. to simply using the quotient of power, follow this :
x^a / x^b = x^( a - b)
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<span>3^10 / 3^4 = 3^6 </span>

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Anybody know the answer to this?
AURORKA [14]
<h3>Answer: Choice B</h3><h3>{4,5,6,7}</h3>

====================================================

Explanation:

Set A = {4,5,6,7,8,9} since these values are larger than 3 and smaller than 10. We only consider whole numbers in this range.

Set B = {1,2,3,4,5,6,7} represents positive whole numbers less than 8

To find the set A \cap B we need to see which values are in both A and B at the same time. Those values are {4,5,6,7}

So A \cap B = \{4,5,6,7\}

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side note: the notation A \cap B means "A intersect B", so we're looking at where the two sets intersect or overlap (ie what they have in common).

6 0
3 years ago
Which of the following numbers is greater than 7.03?
iren [92.7K]

Answer:

A:7.031

Step-by-step explanation:

both 7, but 7.031  has 031.  7.03  only has .03.

4 0
3 years ago
Two buildings are facing each other on a road of width 12 metre . From the top of the first building, which is 10 metre high , t
Karo-lina-s [1.5K]

Answer:

\displaystyle 10 + 12\sqrt{3} <em>metres</em>

Step-by-step explanation:

You are finding the <em>height</em><em> </em>of the building with an angle of elevation, therefore we need to solve for <em>EC</em><em> </em>to add it to <em>BA</em><em> </em>[10 metres] and use TRIGONOMETRIC RATIOS to arrive at our conclusion. Just in case you have forgotten what they were, here they are:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

We can now solve for <em>EC</em>:

\displaystyle cot\:60 = \frac{12}{EC} → ECcot\:60 = 12 \\ \\ \frac{ECcot\:60}{cot\:60} = \frac{12}{cot\:60} → 12\sqrt{3} = EC

<em>OR</em>

\displaystyle tan\:60 = \frac{EC}{12} → 12tan\:60 = EC → 12\sqrt{3} = EC

Now that you have solved for <em>EC</em>, you can now add it to your original 10 metres to get \displaystyle 10 + 12\sqrt{3} <em>metres</em>. As a decimal, you would get \displaystyle 30,78460969... <em>metres</em>. You can go ahead and round this off if necessary.

** The reason why the <em>cotangent</em><em> </em>[or <em>tangent</em>] ratio was used was because <em>EA</em><em> </em>is equivalent to <em>DB</em> by the definition of a rectangle. It has two pairs of parallel and congruent sides with <em>four</em><em> </em><em>right</em><em> </em><em>angles</em>. Plus, that is the <em>adjacent</em><em> </em><em>side</em><em> </em>of the triangle, while <em>EC</em><em> </em>is the <em>opposite</em><em> </em><em>side</em><em> </em>of the triangle, so we knew our ratios were correct.

I am joyous to assist you at any time.

8 0
3 years ago
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