What are the answers to these?

Complete the pattern.5,10,30,60,180,_____

gladu [14]

it would be 360 because it is just multiplying by 2, and then by 3, then back to 2

6 0

3 years ago

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Which law would you use to simplify the expression 3^10/3^4

Fittoniya [83]

When dividing a term with the same constant but different exponents, use the quotient of power rule to simply the given expression. to simply using the quotient of power, follow this :
x^a / x^b = x^( a - b)
3^10 / 3^4 = 3 ^ ( 10 - 4)

3^10 / 3^4 = 3^6

4 0

4 years ago

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Anybody know the answer to this?

AURORKA [14]

<h3>Answer: Choice B</h3><h3>{4,5,6,7}</h3>

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Explanation:

Set A = {4,5,6,7,8,9} since these values are larger than 3 and smaller than 10. We only consider whole numbers in this range.

Set B = {1,2,3,4,5,6,7} represents positive whole numbers less than 8

To find the set $A \cap B$ we need to see which values are in both A and B at the same time. Those values are {4,5,6,7}

So $A \cap B = \{4,5,6,7\}$

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side note: the notation $A \cap B$ means "A intersect B", so we're looking at where the two sets intersect or overlap (ie what they have in common).

6 0

3 years ago

Which of the following numbers is greater than 7.03?

iren [92.7K]

Answer:

A:7.031

Step-by-step explanation:

both 7, but 7.031 has 031. 7.03 only has .03.

4 0

3 years ago

Two buildings are facing each other on a road of width 12 metre . From the top of the first building, which is 10 metre high , t

Karo-lina-s [1.5K]

Answer:

$\displaystyle 10 + 12\sqrt{3}$ metres

Step-by-step explanation:

You are finding the height of the building with an angle of elevation, therefore we need to solve for EC to add it to BA [10 metres] and use TRIGONOMETRIC RATIOS to arrive at our conclusion. Just in case you have forgotten what they were, here they are:

$\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ$

We can now solve for EC:

$\displaystyle cot\:60 = \frac{12}{EC} → ECcot\:60 = 12 \\ \\ \frac{ECcot\:60}{cot\:60} = \frac{12}{cot\:60} → 12\sqrt{3} = EC$

OR

$\displaystyle tan\:60 = \frac{EC}{12} → 12tan\:60 = EC → 12\sqrt{3} = EC$

Now that you have solved for EC, you can now add it to your original 10 metres to get $\displaystyle 10 + 12\sqrt{3}$ metres. As a decimal, you would get $\displaystyle 30,78460969...$ metres. You can go ahead and round this off if necessary.

** The reason why the cotangent [or tangent] ratio was used was because EA is equivalent to DB by the definition of a rectangle. It has two pairs of parallel and congruent sides with four right angles. Plus, that is the adjacent side of the triangle, while EC is the opposite side of the triangle, so we knew our ratios were correct.

I am joyous to assist you at any time.

8 0

3 years ago