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Elis [28]
3 years ago
13

Triangle 4in 5 in and 10in

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

Hello! I am not sure what your question is. Do you want the perimter? Area? soemthing else? Can you give more information?

Step-by-step explanation:

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Help help please i will mark u brill
Roman55 [17]

Answer:

Step-by-step explanation:

u/4 + 9.9 = 16.9

Putting value of u = 24 in the equation

24/4 + 9.9 = 16.9

6 + 9.9 = 16.9

15.9 = 16.9

Bringing like terms on one

16.9 - 15.9 = 1

7 0
3 years ago
Read 2 more answers
How many solutions does this system have <br> 2x+3y=-3<br> 3x+5y=-9
olga nikolaevna [1]

Step-by-step explanation:

please mark me as brainlest

5 0
2 years ago
What is a formula that can be used to find the area of one triangular section of the door? How do you know the formula will work
adoni [48]

Answer:

Area Of a Right Angled∆

=><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>x </u></em><em><u>Base </u></em><em><u>x </u></em><em><u>Height</u></em>

Area of a ∆ Using Heron's Formula

=>

\sqrt{s(s - a)(s - b)( s-c )}

Where

  • S = Semiperimeter
  • a ,b& c = sides of the ∆
3 0
3 years ago
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A school bus during morning pickups to calculate its average speed between 2.8 km and 4.2 km.
kifflom [539]

<u>Answer: </u>

Option (c)

The average speed between 2.8 km and 4.2 km is 42 km/h

<u>Explanation:</u>

Given, the distance between 2.8 km and 4.2 km is 4.2 - 2.8 = 1.4 km

Time (in hours) between 2.8 km and 4.2 km

    = 0.084 – 0.051

     = 0.033 hr

Speed =\frac{Distance}{Time}

Speed = \frac{1.4}{0.033}

Speed = 42.4 km/hr = 42 km/h (rounded to nearest)

Therefore, the average speed between 2.8 km and 4.2 km is 42 km/hr

Hence, Option (C) is correct

4 0
3 years ago
Determine the x- and the y-intercepts of these graphs. a) y = x-2​
Ivanshal [37]

Answer:

y-intercept = (0, -2)

x-intercept = (2, 0)

Step-by-step explanation:

The y-intercept is the value of y when x = 0. Therefore, Given the linear equation, y = x - 2:

Let x = 0:

y = 0 - 2

y = -2.

Therefore, the y-intercept of the linear equation, y = x - 2  is (0, -2).

The x-intercept is the value of x when y = 0.

Therefore, let y = 0:

y = x - 2

0 = x - 2

Isolate x by adding 2 to both sides of the equation:

0 + 2 = x - 2 + 2

2 = x

Therefore, the x-intercept is (2, 0).

5 0
3 years ago
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