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2 years ago

When evaluated, which expression has a result that is a rational number?

Mathematics

1 answer:

emmainna [20.7K]2 years ago

5 0

Answer:

√144 * 0.25 is rational!

Step-by-step explanation:

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Simplify this expression

aliya0001 [1]

Answer:

The answer will be 10

Step-by-step explanation:

15/3*4/2

5*2

=10

6 0

2 years ago

John spent $75 on a shopping trip for new clothes last week. He had expected to spend $100 on clothes.How much was the absolute

ozzi

$25! :)

Good luck! I’d appreciate if you made this the brainliest answer! :)

6 0

3 years ago

Read 2 more answers

Carly is a catcher on the school softball team. By the end of the season, she had played 45% of the 49 games the team played. In

Eduardwww [97]

Carly did not play 22 games

6 0

2 years ago

It is believed that a stock price for a particular company will grow at a rate of $5 per week with a standard deviation of $1. A

IgorLugansk [536]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = $5

For the alternative hypothesis,

µ < $5

number of samples taken = 10

Sample mean, x = (4 + 3 + 2 + 3 + 1 + 7 + 2 + 1 + 1 + 2)/10 = 2.6

To determine sample standard deviation, s

s = √(summation(x - mean)/n

n = 12

Summation(x - mean) = (4 - 2.6)^2 + (3 - 2.6)^2 + (2 - 2.6)^2 + (3 - 2.6)^2 + (1 - 2.6)^2 + (7 - 2.6)^2 + (2 - 2.6)^2 + (1 - 2.6)^2 + (1 - 2.6)^2 + (2 - 2.6)^2 = 30.4

s = √30.4/10 = 1.74

Since the number of samples is 10 and no population standard deviation is given, the distribution is a student's t.

Since n = 10,

Degrees of freedom, df = n - 1 = 10 - 1 = 9

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.6

µ = population mean = 5

s = samples standard deviation = 1.74

t = (2.6 - 5)/(1.74/√10) = - 4.36

We would determine the p value at alpha = 0.05. using the t test calculator. It becomes

p = 0.000912

7 0

2 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of seven errors per page. If more than s

Aleks [24]

Answer:

0.599 is the probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

We are given the following in the question:

The number of typing errors made by a typist has a Poisson distribution.

$\lambda =7$

The probability is given by:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

We have to find the probability that a randomly selected page does not need to be retyped

P(less than or equal to 7 mistakes in a page)

$P( x \leq 7) = P(x =1) + P(x=1) +...+ P(x=6) + P(x = 7)\\\\= \displaystyle\frac{7^0 e^{-7}}{0!} + \displaystyle\frac{7^1 e^{-7}}{1!} +...+ \displaystyle\frac{7^6 e^{-7}}{6!} + \displaystyle\frac{7^7 e^{-7}}{7!} \\\\= 0.59871\approx 0.599$

Thus, 0.599 is the probability that a randomly selected page does not need to be retyped.

4 0

3 years ago