Answer:




Solving for
we got
and replacing this we got:



And then the best option for this case would be:
b.csc x
Step-by-step explanation:
For this case we have the following expression given:

We know from math properties that the definition for cot is 
If we use this definition we got:


Now we can use the following identity:

Solving for
we got
and replacing this we got:



And then the best option for this case would be:
b.csc x
It cost $5 for his brother's ticket.
Step-by-step explanation:
Let,
Micheal's ticket price= x
His brother ticket price = y
According to given statement;
x+y=12 Eqn 1
y = x-2 Eqn 2
Putting value of y from Eqn 2 in Eqn 1

Dividing both sides by 2;

Putting x=7 in Eqn 2

It cost $5 for his brother's ticket.
Keywords: linear equation, substitution method
Learn more about linear equations at:
#LearnwithBrainly
Answer:
A (50)
Step-by-step explanation:
Mean is the total numbers added up divided by the # of numbers.
There are 6 numbers.
51 + 60 + 80 + 32 + 47 + 30 = 300
300/6 = 50
Therefore, the answer is A.
Answer:
a. True
b. True
c. False
d. False
Step-by-step explanation:
<u>First Table</u>
Length=10 feet, Width=4 feet
Area =10 X 4=40 Square Feet
<u>Second Table</u>
The second table is half as long as the first table.
Length =0.5 X 10 =5 feet
Area=5 X Width= 5w
The area of the second table is one fourth the area of the first table.
Area of Second Table =
X Area of first table
5w=
X 40
5w=10
Width of the Second table, w=2 feet
The following are true.
(a)The width of the second table is 2 feet.
(b) The area of the second table is 10 square feet.
Attached is your solution: simply set up the box as shown, then find the product of each in individual square in the box. The solution is the sum of the products... Note that when multiplying two binomials, you'll have like terms on one diagonal.
Hope this helps.. let me know if you have questions.