Just multiply 1/6 it's the scale factor so it'll tell you how you will shrink or enlarge the length
Answer:
See below
Step-by-step explanation:
From noon to 1500 is three hours
train A then travels <u> 3x</u> where x = speed in km/hr
train B only travels for 2.45 hours and covers
<u> 2.45 ( x + 15) </u> where x + 15 is its speed in km/hr
these two values sum to the 300 km distance
3x + 2.45 ( x + 15) = 300
3x + 2.45 x + 36.75 = 300
x = 48.3 km/hr x+15= 63.3 km / hr
I have to think this through.... I will get back later 2.222
Option I
(3x+4)cm =(2x+10)cm
3x-2x=6
x=6
Option II
(3x+4)= (x+12)
3x-x=12-4
2x=8
x=4
Option III
(2x+10)= (x+12)
2x-x=12-10
x=2
