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In-s [12.5K]
3 years ago
13

What is the approximate volume of the cylinder use 3.14 for π​

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

904.32 cm²

Step-by-step explanation:

V = πr²h

V = 3.14 × (6 cm)² × 8 cm

V = 904.32 cm²

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An aerosol can contains gases under a pressure
slavikrds [6]

Answer:

temperature on the beach = T2 = 34.56 °C

Step-by-step explanation:

We are given;

P1 = 4.5 atm

T1 = 24 °C = 24 + 273 = 297 K

P2 = 4.66 atm

Thus, P1/T1 = P2 /T2

So, T2 = P2•T1/P1

Thus, T2 = (4.66x 297)/4.5

T2 = 307.56 K

Let's convert to °C to obtain ;

T2 = 307.56 - 273

T2 = 34.56 °C

7 0
3 years ago
Can you solve -4a^ - (6a-2) + 3 (a^-1).the arrows that are pointing up is exponent 2.also please show work
Burka [1]
First step is to distribute.
-4a^2 - 6a +2 + 3a^2 -3
Combine like terms
-a^2 -6a -1
5 0
3 years ago
You want to buy a bouquet of yellow roses and baby’s breath for $16 the baby’s breath cost $3.50 per bunch, and the roses cost $
Stolb23 [73]

•.,¸¸,.•´¯     '     ¯´•.,¸¸,.•`

: 5 !!! !

3 0
3 years ago
A bar of soap is shaped like a right rectangular prism. The base is a rectangle that is 12 centimeters by 2 centimeters. The hei
evablogger [386]

Answer:

6 cm

Step-by-step explanation:

Volume of a Prism = base area x height =

Base area = length x width =  12 x 2 = 24 cm^2

Volume = 24 x 3 = 72 cm^3

Volume of a pyramid = 1/3( l x w x h)

72 = 1/3( 6x6 x h)

Multiply both sides of the equation by 3

216 = 36 x h

divide both sides by 36

h = 6

8 0
3 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
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