<h2>
Answer with explanation:</h2>
Let 
be the population mean.
By observing the given information, we have :-
Since the alternative hypotheses is left tailed so the test is a right-tailed test.
We assume that the time spend by students per day is normally distributed.
Given : Sample size : n=121 , since n>30 so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-
Critical value (one-tailed) corresponds to the given significance level :-
Since the observed value of z (-7.79) is less than the critical value (1.2816) , so we do not reject the null hypothesis.
Hence, we conclude that we have enough evidence to accept that the college students spend an average of 4 hours or less studying per day.
The answer is 28. 7x2=14 and then 14x2=28. Remember PEMDAS
Answer:
Step-by-step explanation:
Let 
So 
Let 
We are going to find 
So we are evaluating 
First step find f(-2)
Second step find f'(-2)
Third step plug in those values and apply PEMDAS!
So
We first find the zeros of the function , the zeros of the function are those at which points the graph of the function crosses or touches the x axis
here we can see in the graph that graph crosses the x axis at two points , 1 and 7
So the zeros of the function are
x=1 and x=7
It means the factor are
(x-1) and (x-7)
So the factorization is given by
(x-1)(x-7)
Answer: p=-7
Step-by-step explanation:
To solve for p, you want to isolate the variable, get p alone. You would use different algebraic properties to do so.
30+6p=7p+42-5
30+6p=7p+37
-7=p
p=-7
