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Korvikt [17]
3 years ago
12

.What is the rate of change of the line that passes through (8,6) and (12,14)? ​

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0
This way u can get the answer


First, there are several terms that mean SLOPE"
m in y = mx + b
rate of change
incline
grade
"rise over run"
slant
incline
. . .
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Quadrilateral ABCD is dilated by a scale factor of 1/3 centered around (1,2). Which statement is true about the dilation
morpeh [17]

Answer:

I cannot help answer this question if you don't add the statements...

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A rotating lawn sprinkler sprays water in a circular area of grass as shown in the picture. The diameter of the circular area of
Georgia [21]

Answer:

9\pi \: \mathrm{ft^2\:or}\: 28.27 \mathrm{\: ft^2}

Step-by-step explanation:

The area of a circle is given by r^2\pi where r is the radius of the circle. The diameter is given as 6 feet, so the radius of this circle is \frac{6}{2}=3 feet.

Plugging in our values, we get:

3^2\pi=9\pi\approx28.27.

7 0
2 years ago
Textbooks are exempted from PST in Ontario. If the total cost of a book
Andrei [34K]

Answer:

4.24

Step-by-step explanation:

Total price = price of the book + 5% of the price of the book

T = total price   P = price of the book G = GST

T = P + G

and

G = 5% of P = 0.05P

therefore

T = P + 5%P = 1P + 0,05P = 1.05P

P = T/1.05 = 89/1.05 ≅ 84.76 (it is 84.7619047619)

G = 89 - 84.76 = 4.24

8 0
3 years ago
What inequality represents the following sentence?
Maurinko [17]
C.

Hope this helps! :)
7 0
3 years ago
Express answer in exact form.
Kruka [31]
We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²

area of a circle=pi*r²

in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²

the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of ​​the circle minus the area of ​​1 equilateral triangle
</span>so
 [ (3/2)*pi in²-(9/4)*√3 in²]

the answer is
 [ (3/2)*pi in²-(9/4)*√3 in²]

6 0
3 years ago
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