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anastassius [24]
3 years ago
15

The length or a rectangular floor is 5 feet less than twice it’s it’s width. The area of the floor is 150 square feet. What is t

he width or the room?
Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0
<span>L=2W-5
LW=150
(2W+5)W=150
2W^2+5W-150=0
(2W-15)(W+10)=0
2W-15=0                </span>2W=15<span>W=7.5 ANS. FOR THE WIDTH.
L=2*7.5+5
L=15+5
L=20 ANS. FOR THE LENGTH.

20*7.5=150
</span><span>150=150</span> 
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Step-by-step explanation:

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Arbara signed up for dance lessons at Dance Unlimited. She was charged $55 per month for lessons and a one-time recital fee of $
kramer

Given:

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One-time recital fee = $165

The equation represents the $495 total cost that Barbara paid to Dance Unlimited.

495=165+55m

To find:

We need to find the number of month Barbara receive dance lessons from Dance Unlimited.

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495=165+55m

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8 0
3 years ago
Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand
Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2  

And a standard deviation of 3.6.  

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6  

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1

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Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0
3 years ago
Please help ASAP<br> Please help ASAP<br> Please help ASAP<br> Please help ASAP
dedylja [7]

Substituting L = 7.29,

t = 2.01 \sqrt{7.29} \approx \boxed {5.4}

5 0
2 years ago
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