I do not see anything wrong with it
As you increase the subintervals the area will be closer and closer to the real value. In other words your approximation gets better.
As you increase the intervals, there will be more rectanagles and the added area of these rectangles are converging towards the actual area under the curve.
Answer:
f(g(x)) = 2(x^2 + 2x)^2
f(g(x)) = 2x^4 + 8x^3 + 8x^2
Step-by-step explanation:
Given;
f(x) = 2x^2
g(x) = x^2 + 2x
To derive the expression for f(g(x)), we will substitute x in f(x) with g(x).
f(g(x)) = 2(g(x))^2
f(g(x)) = 2(x^2 + 2x)^2
Expanding the equation;
f(g(x)) = 2(x^2 + 2x)(x^2 + 2x)
f(g(x)) = 2(x^4 + 2x^3 + 2x^3 + 4x^2)
f(g(x)) = 2(x^4 + 4x^3 + 4x^2)
f(g(x)) = 2x^4 + 8x^3 + 8x^2
Hope this helps...
The standard form: Ax + By = C
3x - y = -6 YES - A = 3, B = -1, C = -6
3x + y = 6 YES - A = 3, B = 1, C = 6
x + 6y = 9 YES - A = 1, B = 6, C = 9
x - 6y = -9 YES - A = 1, B = -6, C = -9
