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3 years ago

SOMEONE HELP ME WITH THIS PROOF

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

6 0

Okay, for this proof, I'll write the steps out.

Statements:
1. ABCD is a parallelogram
2. FG bisects DB
3. <GEB ≡ (pretend congruent symbol) <FED
4. DE ≡ BE
5. <CDA ≡ <ABC
6. < CDB ≡ <DBA
7. triangle DFE ≡ triangle BGE
8. FE ≡ GE
9. DB bisects FG

Reasons:
1. Given
2. Given
3. vertical angles are congruent
4. If bisected, then split into congruent parts
5. opposite angles of a parallelogram are congruent
6. Subtraction Property
7. ASA
8. CPCTC
9. segment split into congruent parts by other segment is bisected.

Hope this helped! :)

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You are given the following system.x=2y+42x-3y=11 What method would you use to solve this system?

qwelly [4]

Answer:

substitution

Step-by-step explanation:

We assume the two equations are ...

x = 2y+4
2x -3y = 11

You are given an expression for x. Using that in the second equation will result in an immediate solution for y.

... 2(2y+4) -3y = 11 . . . . . substituting 2y+4 for x

.. y +8 = 11

... y = 3

... x = 2·3 +4 = 10

The solution is (x, y) = (10, 3)

7 0

4 years ago

Which of the following ordered pairs represents the solution to the system given below? 2x + y = 20 4x − 2y = 40 A) (10,0) B) (0

shtirl [24]

$2x+y=20 \ \ \ |\times 2 \\
4x-2y=40 \\ \\
4x+2y=40 \\
\underline{4x-2y=40} \\
4x+4x=40+40 \\
8x=80 \ \ \ |\div 8 \\
x=10 \\ \\
2x+y=20 \\
2 \times 10+y=20 \\
20+y=20 \ \ \ |-20 \\
y=0 \\ \\
\boxed{(x,y)=(10,0)} \Leftarrow \hbox{answer A}$

4 0

3 years ago

Read 2 more answers

Relations and Functions, please help with these 3 questions asap. I will give brainliest! Only answer if you know how to do this

gladu [14]

<h2> Question # 1</h2>

Part A) Is the relation a function? Explain.

A function relates each element of a set with exactly one element of another set.

Important things for a relationship to be a function:

Every element in X is related to some element in Y.

A function cannot have one-to-many relationship.

A function must contain single valued, means it is not having one-to-many relation

Considering the points on coordinate plane

(-4, 2), (-3, 0), (-2, -1), (0, 2), (2, -3), (3, 3)

If we carefully observe, we determine that relation

relates each element of a set with exactly one element of another set

is single-valued, means It is not giving back 2 or more results for the same input. In other words, it is not having one-to-many relation.

It is in fact, having many to one. For example, the pairs (0, 2) and (-4, 2) is having many- to-one relationship.

So, from the above observation, it is clear that the relationship is a function.

Part B) What is the domain of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

Also we know that domain of the relation is the set of all the x-values of an ordered pairs.

So, the domain of the relation: {-4, -3, -2, 0, 2, 3}

Part C) What is the range of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

As we know that the range of a relationship is the set of all the y-values of an ordered pair.

So, the range of the relationship will be: { -3, -1, 0, 2, 3}

<em>Note:</em>

The duplicated entries in the domain and range are written only once.
Also, the domain and range can be written in ascending order.

Part D) What is the value of y when x = 2? Explain

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

From the given points on the coordinate plane, it is clear that when the value of x = 2, then the value of y = -3

Therefore, the value of y is -2 when x = 2

<h2> Question # 2</h2>

Considering the points on coordinate plane

(-4, -1), (-2, 1), (0, -3), (2, 3), (4, -2)

If we bring a point, let say (2, 4), and graphed on the coordinate system, then the relation will no longer be function.

The reason is that the induction of the point (2, 4) would violate the definition of a relation to be a function.

Observe that (2, 4) and (2, 3) will make the relation having one-to-many relationship as (2, 4) and (2, 3) is giving 2 outputs i.e. y = 4, and y = 3 for a single input i.e. x = 2.

Therefore, the induction of the point (2, 4), when graphed, makes the relation not a function.

<h2> Question # 3</h2>

Part A)

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ ; $x = -5$

The attached figure a shows the graph for the function

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

In the attached figure a, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -5

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

$|\left-5\right\:-\:3|\:-\:2....[A]$

Solving

$\left|-5-3\right|$

$\mathrm{Subtract\:the\:numbers:}\:-5-3=-8$

$=\left|-8\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a$

$\left|-8\right|=8$

So,

$\left|-5-3\right|=8$

Equation [A] becomes

$\:|-5\:-\:3|\:-\:2\:=8\:-\:2\:$ ∵ $\left|-5-3\right|=8$

$=6$

Therefore,

the value of $f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ at $x = -5$ will be 6.

i.e. $f(x)=6$

<h2 />

Part B)

$g\left(x\right)=1.5x;\:x=0.2$

The attached figure b shows the graph for the function

$g\left(x\right)=1.5x$

In the attached figure b, the graph shows that the function represents a linear relationship as the graph is a straight line.

Evaluate the function for x = 0.2

$g\left(x\right)=1.5x$

Putting x = 0.2

$g\left(x\right)=1.5\left(0.2\right)$

$1.5\left(0.2\right)=0.3$

$g\left(x\right)=0.3$

So,

the value of $g\left(x\right)=1.5x$ at $x = 0.2$ will be 0.3.

i.e. $g\left(x\right)=0.3$

Part C)

$p\left(x\right)\:=\:|7\:-\:2x|;\:x\:=\:-3$

As the absolute value of a number will be never negative.

The attached figure c shows the graph for the function

$p\left(x\right)\:=\:|7\:-\:2x|$

In the attached figure c, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -3

$p\left(x\right)\:=\:|7\:-\:2x|$

Solving

$\left|7-2x\right|$

$\left|7-2\left(-3\right)\right|$

$=\left|7+6\right|$

$=\left|13\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$=13$

So,

$\left|7-2x\right|=13$

So,

the value of $p\left(x\right)\:=\:|7\:-\:2x|$ at $x = -3$ will be 13.

i.e $p\left(x\right)\:=13$

Keywords: function, relation

Learn more about functions from brainly.com/question/2335371

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3 0

4 years ago

I need help on this question

Alinara [238K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

• Check your work when you're done.

Triss [41]

If Glen get a yellow marble first then we have 2 yellow marbles...probability that Glen will get yellow marble is 2/5(we have just 2 yellow now and the total is 5)
2/5-answer☺️

3 0

3 years ago