The perimeter doesn't tell you the dimensions.
With a 40-ft perimeter, there an infinite number of possibilities
for the length and with. The only thing we know for sure is that
the sum of (length + width) is 20-ft.
The field could be . . .
1' by 40'
2' by 20'
3' by 13-1/3 '
4' by 10'
5' by 8'
6' by 6-2/3 '
solution: x+5= -x-5
x= -5
1. Subtract 5 from both sides
2. Simplify
3. Add x from both sides
4. Simplify
5. Divide both sides by two
Let T represent the fifth test score. The average is the sum of scores divided by their number.
... 82 = (83 +75 +93 +67 +T)/5
... 410 = 318 +T . . . . . . . multiply by 5
... 92 = T . . . . . . . . . . . . subtract 318
The fifth score was 92.
_____
One of the ways I like to work problems like these is to add the differences from the mean. Those are ...
1, -7, 11, -15
so their sum is -10.
The final score must be 10 above the mean in order for this total to be zero. 10 above the mean is 92.
Answer:
Step-by-step explanation:
If the two triangles what?
Answer:
3√2
Step-by-step explanation:
this is called 45° ~ 45°~ 90° special triangle
the right angles has a length of x while hypotenuse has x√2
since in this triangle the given right sides' length = 3, hypotenuse must be = 3√2
