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avanturin [10]
4 years ago
14

What is the fraction ofr 0.0625?

Mathematics
2 answers:
Sunny_sXe [5.5K]4 years ago
4 0
The fraction of 0.0625 is 1/16
Bezzdna [24]4 years ago
4 0
The answer is 1/16 cause it was 625/1000 and if u reduce it u get 1/16. Happy to help!! :)
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In his suitcase, Jack has 3 shirts, 4 pants, 2 socks (pairs of socks), and 2 shoes (pairs of shoes). How many unique ways can Ja
kipiarov [429]

Answer:

48

Step-by-step explanation:

the number of shirts are 3, number of pants 4, number of socks pairs 2 and 2 pairs of shoes.

first lets start with shirts and pants, number of unique combinations are,

(for each shirt there are 4 different pant combinations) = (3)(4)

=12

similiarly for each shirt pant pair there are 2 shoes and 2 socks pairs.

thus, total number of combinations are=

(12)(2)(2)

= 48

8 0
4 years ago
Rita drove 792 miles in 11 hours.
Talja [164]

Answer:

Step-by-step explanation:

Let's write an expression.

Let's say m is miles and h is hours.

792m = 11h

Simplify.

11 ÷ 11 = 1

792 ÷ 11 = 72

Let's rewrite our expression.

72m = 1h

Using this formula, you can solve anything! :)

6 0
4 years ago
What is 12/35 simplified
Amiraneli [1.4K]

12/35 cannot be simplified further. To check, divide each of them by the same number. If u cannot get a whole number for both, this means that your fraction cannot be simplified.

Thx!

4 0
4 years ago
Read 2 more answers
The Pirerras are planning to go to Europe 3 years from now and have agreed to set aside $140/month for their trip. If they depos
Natalka [10]

Answer:

(a)$5805.21

(b)Least Expensive Mortgage =$120640.59

Most Expensive Mortgage =$152032.77

Step-by-step explanation:

The future value of an ordinary annuity with deposits P made regularly k times each year for n years, with interest compounded times k per year at an annual rate r, is given as:

F.V.=\dfrac{P[(1+i)^{kn}-1]}{i}

The Pirerra's Monthly Payments=$140

Annual Rate =9.5%

Therefore: Monthly Rate=0.095/12

Years, n=3

Period, k=12

F.V.=\dfrac{140[(1+\frac{0.095}{12} )^{3*12}-1]}{\frac{0.095}{12} }=\$5805.21

(b)For the Johnsons, Present value of Mortgage is derived using the formula:

\Text{Present Lump Sum}, A_0=\dfrac{P[1-(1+i)^{-kt}]}{\frac{r}{k} }

At $1000 Monthly payment

\Text{Present Lump Sum}, A_0=\dfrac{1000[1-(1+\frac{0.08}{12} )^{-12*15}]}{\frac{0.08}{12} }=\$104640.59

Adding  a down payment of $16000

  • Least Expensive Mortgage = 104640.59+16000=$120640.59

At $1300 Monthly Payment

\Text{Present Lump Sum}, A_0=\dfrac{1300[1-(1+\frac{0.08}{12} )^{-12*15}]}{\frac{0.08}{12} }=\$136032.77

Adding  a down payment of $16000

  • Most Expensive Mortgage = 136032.77+16000=$152032.77
4 0
3 years ago
Combine like terms to complete the equivalent expression. 2 1/2 z² + 4 1/2 + 7z - 4 +5z - 1/2 z² = ( _ z² - _z²) + ( 7z + _ z) +
postnew [5]

Step-by-step explanation:

z is 1 and 2 is 2

8 0
3 years ago
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