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Ugo [173]
3 years ago
15

Two similar cylinders have radii of 15 inches and 6 inches. What is the ratio of the surface area of the small cylinder to the s

urface area of the large cylinder.
Mathematics
1 answer:
Levart [38]3 years ago
8 0

Answer:

4:25

Step-by-step explanation:

Given that,

r₁ = 15 inches, r₂ = 6 inches

The area of the cylinder is given by :

A=2\pi rh+2\pi r^2

The ratio of surface areas of two cylinders,

\dfrac{S_2}{S_1}=\dfrac{2\pi r_2h_2+2\pi r_2^2}{2\pi r_1h_1+2\pi r_1^2}\\\\\dfrac{S_2}{S_1}=(\dfrac{r_2}{r_1})^2\\\\=\dfrac{6}{15}^2\\\\=\dfrac{4}{25}

Hence, the required ratio is 4:25.

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Answer:

The relation for the area of circle with radius , Diameter , circumference is

A=   \pi × radius²

A = \frac{\pi D^{2} }{4}

A = \frac{c^{2} }{4\pi }

Step-by-step explanation:

Given as :

The formula for the area of circle = \pi × radius²

I.e A =  \pi × radius²

<u>Now If we know radius then </u>

Area calculated as A=   \pi × radius²

<u>If we know Diameter then</u>

Area calculated as   \pi × (\dfrac{\textrm Diameter}{2})²

Or, A =   \pi × (\dfrac{\textrm D}{2})²

I,e  A = \frac{\pi D^{2} }{4}

<u>If we know the circumference then</u>

∵ circumference = c = 2 × \pi × radius

or, c =  2 × \pi × r

from here we calculate radius

I.e  r = \frac{c}{2\pi  }

And So , Area ( A ) = \pi × radius²

I.e   A = \pi × ( \frac{c}{2\pi  } )²

Or, A = \frac{c^{2} }{4\pi }

Hence The relation for the area of circle with radius , Diameter , circumference is

A=   \pi × radius²

A = \frac{\pi D^{2} }{4}

A = \frac{c^{2} }{4\pi }      Answer

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