HAHA so cool maybe, cafe
2 answers:
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Answer:
D. f(x) exist for all real numbers where x ≤ -1 or x ≥ 1
Explanation:
You can't divide by 0 and
You can't have a negative squareroot.
So solve for when x=0 for the denominator,
and when is x<0 for the squareroot.
