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ipn [44]
2 years ago
9

What's the real power of a purely resistive circuit in which the RMS voltage measures 80 volts and the RMS current measures 5 am

ps?
A. 85 watts

B. 120 watts

C. 240 watts

D. 400 watts
Advanced Placement (AP)
2 answers:
Marina86 [1]2 years ago
4 0

Answer:

400 watts

Explanation:

Given purely resistive circuit,

that implies power factor, cos \phi = 1.

RMS Voltage, VRMS = 80 V.

RMS Current, IRMS = 5 A.

Real power, P = VRMS * IRMS* cos \phi

P = 80*5*1 = 400 W

Hence, P = 400 W.

mash [69]2 years ago
4 0

Answer:

400 watts

Please give me brainliest! you would get 25% as well!

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