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topjm [15]
2 years ago
8

Solve using the quadratic formula: 2n^2= 6n - 2

Mathematics
1 answer:
bekas [8.4K]2 years ago
3 0

Answer:

n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2

Step-by-step explanation:

2n^2= 6n - 2\\\\2n^2-6n+2=0\\\\a=2\\\\b=-6\\\\c=2

n=(-b \pm \sqrt{b^2-4ac} )/2a\\\\n=(-(-6) \pm \sqrt{(-6)^2-4(2)(2)} )/2(2)\\\\n=(6 \pm \sqrt{36-16} )/4\\\\n=(6 \pm \sqrt{20} )/4\\\\n=(6 \pm 2\sqrt{5} )/4\\\\n=(3 \pm 1\sqrt{5} )/2\\\\n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2

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Answer:

I assume you know Arithmetic Progression .

so, we have to find the first and last 4-digit number divisible by 5

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here, a_{n} is the last 4-digit number divisible by 5.

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