Answer:
the sample standard deviation is 4.926 pounds
Step-by-step explanation:
the sample standard deviation s is defined as
s =√[ 1/(n-1) ∑ ( x- m)²] for x=1 to x=n
where
n= sample size = 10
x= weights of defensive tackles
m= sample mean
m= 1/n ∑ x* for x=1 to x=n
then
m= 1/10 (202 + 215... +208) = 209.66 pounds
thus
s =√[ 1/(10-1) ∑ ( x- m)²] = √[ 1/(10-1) [ ( 202 - 209.66 )² + ( 215 - 209.66 )² + ( 28 - 209.66 )² ] ] = 4.926 pounds
then the sample standard deviation is 4.926 pounds
