Complete question is;
In a race that consisted of three parts, the cycling part was 12 1/2 miles long. The running part of the race was 1/4 the distance of the cycling part. The kayaking part of the race was 1/2 the distance of the running part. What was the entire distance, in miles of the race?
Answer:
Total distance of race = 17.1875 miles
Step-by-step explanation:
The 3 parts of the race are; cycling, running and kayaking.
The cycling distance was; 12½ miles
We are told that the running part was ¼ of the cycling distance. Thus;
Running distance = ¼ x 12½ = ¼ x 25/2 = 25/8 miles
Lastly, we are told that the kayaking part was ½ the distance of the running part. Thus;
Kayaking distance = ½ x 25/8 = 25/16
Thus,total distance of race = cycling distance + running distance + kayaking distance = 12½ + 25/8 + 25/16 = 17.1875 miles
Where the thing h buubbububuubub
Answer:
f=2
Step-by-step explanation:
0.3+0.5f-0.7
Move the varibale (0.5f) to the left-hand side and change it's sign to negative.
-0.5+0.3+-0.7
Move the constant to the right hand side and change it's sign
-0.5f=-0.7-0.3
Calulate the differnce
-0.5f=-1
divide both sides by -0.5
F=2
Answer:
y < -3/2x -2
Step-by-step explanation:
Used Desmos graphing calculator
Answer:
Sin theta = 12/13
Step-by-step explanation:
From the question;
Cot theta = 5/12
Kindly recall;
Cot theta = 1/ tan theta
Hence, tan theta = 12/5
Mathematically
tan theta= opposite/adjacent
to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides
let hypotenuse be h
h^2 = 12^2 + 5^2
h^2 = 144 + 25
h^2 = 169
h = √169
h = 13
But sine theta = opposite/ hypotenuse = 12/13
