At constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.
<h3>
Boyle's law</h3>
Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Given the data in the question question;
- Initial volume of the gas V₁ = 30.0mL = 0.03L
- Initial pressure of the gas P₁ = 1.53atm
- Final volume of the gas V₂ = 50.1mL = 0.0501L
- Final pressure of the gas P₂ = ?
We substitute our given values into the expression above to determine the new pressure.
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = ( 1.53atm × 0.03L ) / 0.0501L
P₂ = 0.0459Latm / 0.0501L
P₂ = 0.92atm
Therefore, at constant temperature, if the volume of the sample of gas increases to the given value, the pressure decreases to 0.92atm.
Learn more about Boyle's law here: brainly.com/question/1437490
I am assuming that the problem ask for the pressure in
the system. To be able to calculate this, we first assume that the system acts
like an ideal gas, then we can use the ideal gas equation to find for pressure
P.
P V = n R T
where,
P = Pressure (unknown)
V = 0.17 m^3
n = moles of lng / methane
R = gas constant = 8.314 Pa m^3 / mol K
T = 200 K
We find for the moles of lng. Molar mass of methane = 16
kg / kmol
n = 55 kg / 16 kg / kmol
n = 3.44 kmol CH4 = 3440 mol
Substituting all the values to the ideal gas equation:
P = 3440 mol * (8.314 Pa m^3 / mol K) * 200 K / 0.17 m^3
P = 33,647,247 Pa
<span>P = 33.6 MPa</span>
Answer:
The greater the frequency means the more energy transferred.
The greater the wavelength means the less energy transferred