Here you are giving only the amount they want to raise (namely profit times number of magazines sold), and here you are also giving Money they want to raise... So clarifying, the money they want to raise, should include the money they will spend on buying the magazines (there is no statement saying they found them, or were given the magazines, so a cost should be involved)
Now if they are only making the count of "Field trip costs X amount of money, and given we have to make a profit of $5.5, How many must we sell?" then the equation should be n=X/5.5
Should the story be, how much money must they raise to have a profit of 5.5 on each magazine and still have enough for the field trip, then you have a different equation which varies only in adding the cost of each magazine, either case, M should be defined not as money they need to raise (cause here they will be short on their goal) but Money they must earn. And again, you should rewrite your equation to be:
M=Amount they must raise
C=Cost per magazine
n=Number of magazines
p=profit $5.5 per magazine
C+p=M/n
And rewriting the previous they should make:
n(C+p)=M -----> n(C+5.5)=M <span>m/n = 5.50 </span>
<span>m/n x n = 5.50 x n //// multiply each side by n </span>
<span>m = 5.5n</span>
32 models need to make model of 3200.
Given that a 1 model contain 100.
Two series of numbers, usually empirical data, that are proportional or proportional if their respective elements are in constant proportion, called the scaling factor or the rate constant.
One model has 100 elements.
Now, we have to find how many model contains 3200 elements.
So, 1 model=100 elements
n model =3200 elements
We will write this in proportion as
1/n=100/3200
Applying the cross multiply, we get
3200×1=n×100
Divide both sides with 100, we get
3200/100=100n/100
3200/100=n
32=n
Hence, the 32 models contain 3200 elements when one contain 100 elements.
Learn more about proportional from here brainly.com/question/23536327
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Answer:
x+6.3
Step-by-step explanation:
x+6.3
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Answer:
x = number of nickels = 127
y = number of dimes = 156
z = number of quarters = 78
Step-by-step explanation:
Let
x = number of nickels
y = number of dimes
z = number of quarters
Total worth of the coins = $41.45
Total number of coins = 361
x + y + z = 361 (1)
dime = $0.1,
nickel = $0.05
quarter = $0.25
0.05x + 0.1y + 0.25z = 41.45 (2)
twice as many dimes as quarters.
y = 2z
Substitute y = 2z into (1) and (2)
x + 2z + z = 361
0.05x + 0.1(2z) + 0.25z = 41.45
x + 3z = 361
0.05x + 0.2z + 0.25z = 41.45
x + 3z = 361 (3)
0.05x + 0.45z = 41.45 (4)
Multiply (4) by 20
x + 3z = 361 (3)
x + 9z = 829 (5)
Subtract (3) from (5)
9z - 3z = 829 - 361
6z = 468
Divide both sides by 6
z = 468 / 6
= 78
z= 78
Recall,
y = 2z
= 2(78)
= 156
y = 156
Substitute the value of y and z into
x + y + z = 361
x + 156 + 78 = 361
x + 234 = 361
x = 361 - 234
= 127
x= 127
x = number of nickels = 127
y = number of dimes = 156
z = number of quarters = 78
For the first system, we have
1 - 3x + 3y = -8
or
-3x + 3y = -9
The second equation, however, tells us
-3x + 3y = 13
but -9 ≠ 13, so this system has no solution.
For the second system, notice that multiplying both sides of
4x - 8y = 6
by 1/2 gives
2x - 4y = 3
which is identical to the other equation in the system. Then all point (x, y) that lie on this line are solutions to the system, meaning there are infinitely many solutions.
