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nydimaria [60]
3 years ago
5

Need help ASAP

Mathematics
2 answers:
aliina [53]3 years ago
7 0

Answer:

<h2>equivalent</h2>

Step-by-step explanation:

2x + 3 = x/2 + 4

2x - x/2 = 4 - 3

3x/2 = 1

x = 1 (2) / 3

x = 2/3

substitute the value of x=2/3 back into the equation:

2(2/3) + 3 = (2/3)/2 + 4

4/3 + 3 = 1/3 + 4

<h3>13/3 = 13/3  both are equal if x=2/3</h3>
9966 [12]3 years ago
3 0

Answer:

YES

Step-by-step explanation:

COZ I SEE

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Let h(x)=20e^kx where k ɛ R (Picture attached. Thank you so much!)
zloy xaker [14]

Answer:

A)

k=0

B)

\displaystyle \begin{aligned} 2k + 1& = 2\ln 20 + 1 \\ &\approx 2.3863\end{aligned}

C)

\displaystyle \begin{aligned} k - 3&= \ln \frac{1}{2} - 3 \\ &\approx-3.6931 \end{aligned}

Step-by-step explanation:

We are given the function:

\displaystyle h(x) = 20e^{kx} \text{ where } k \in \mathbb{R}

A)

Given that h(1) = 20, we want to find <em>k</em>.

h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

\displaystyle (20) = 20e^{k(1)}

Simplify:

1= e^k

Anything raised to zero (except for zero) is one. Therefore:

k=0

B)

Given that h(1) = 40, we want to find 2<em>k</em> + 1.

Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

\displaystyle (40) = 20e^{k(1)}

Simplify:

\displaystyle 2 = e^{k}

We can take the natural log of both sides:

\displaystyle \ln 2 = \underbrace{k\ln e}_{\ln a^b = b\ln a}

By definition, ln(e) = 1. Hence:

\displaystyle k = \ln 2

Therefore:

2k+1 = 2\ln 2+ 1 \approx 2.3863

C)

Given that h(1) = 10, we want to find <em>k</em> - 3.

Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

\displaystyle (10) = 20e^{k(1)}

Simplfy:

\displaystyle \frac{1}{2} = e^k

Take the natural log of both sides:

\displaystyle \ln \frac{1}{2} = k\ln e

Therefore:

\displaystyle k = \ln \frac{1}{2}

Therefore:

\displaystyle k - 3 = \ln\frac{1}{2} - 3\approx-3.6931

3 0
2 years ago
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kotegsom [21]

Answer:

$19.136

Step-by-step explanation:

if 100% ----> $16.64

then 115% ----> $19.136

hope this helps :)

5 0
2 years ago
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Answer:

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Step-by-step explanation:

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