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pychu [463]
3 years ago
14

A parent function f(x)=4x-5 is transformed to f(x)+3. which statement about the graph of f(x)+3 is true?

Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

B

Step-by-step explanation:

f(x) is just another way of saying y, so this function is really y=4x-5. So if you do y+3 then the y intercept will increase by 3 shifting the graph up 3 units.

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8x + 34. What does X equal
rosijanka [135]

Answer: x=-4.25

Step-by-step explanation:

First you put it in to y= mx+b form.

0=8x+34

Then you subtract 34 from both sides

-34=8x

Then you divide 8 from both sides

Leaving you with

x=-4.25

4 0
3 years ago
Please find the slope of (-2, 4) and (3, -5)
DIA [1.3K]

Answer:

The slope of the line = m = -9/5

Step-by-step explanation:

Given the points

  • (-2, 4)
  • (3, -5)  

Determining the slope between (-2, 4) and (3, -5)

(x₁, y₁) = (-2, 4)

(x₂, y₂) = (3, -5)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]  

                 =  [-5 - 4] / [3 - (-2)]

                 = [-9] / [3 + 2]

                 = -9/5

Thus, the slope of the line = m = -9/5  

8 0
3 years ago
Which best explains what happens during crossing over?
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I have to determine the length please show me the steps
iogann1982 [59]

Answer:

c = 11.03 m

Step-by-step explanation:

In this given <em>right isoceles triangle</em>, one of the sides are labeled as 7.8 m. We'll label this side as "a."  

The length of side "a" is congruent to the other side. Therefore, the measurement of the other side is also 7.8 m.

We can use the Pythagorean Theorem to solve for the measurement of the hypotenuse, side "c."

According to the Pythagorean Theorem: c^{2} =  a^{2} + a^{2}.

We'll plug in the values for side "a" and side "b" into the formula:

c^{2} =  a^{2} + a^{2}

c^{2} =  2a^{2}

c^{2} =  2(7.8 m)^{2}

c^{2} =  121.68 m^{2}

To calculate the value of "c," we must take the squared root of 2a^{2}:

\sqrt{c^{2}}  = \sqrt{121.68}

c = 11.03087 m or 11.03 m

By the way, the value of c = <em>a </em>\sqrt{2}

8 0
3 years ago
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