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bulgar [2K]
3 years ago
8

Simplify 9^2 over 9^7

Mathematics
1 answer:
Illusion [34]3 years ago
3 0
1/59049 !!!!!!!!!!!!!!!!!!!!
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Find the measure of each angle.<br><br> m∠BAC=<br> m∠CAD=
NARA [144]

i dont have much time to go through all the work but i can tell you that since its a 90 degree angle, your equation would be 90=15x-2+7x+4. Once you get the value of X plug that into each of the equations. For example if your x value was 2 you would do 15(2)-2. Thats just an example.

7 0
3 years ago
Read 2 more answers
a company uses two vans to transport workers from a free parking lot to the work place between 7:00 and 9:00 am one van has 6 mo
k0ka [10]
So first, I would assign the small van a variable for how many people it can hold, or x.

So since it makes two trips,

2x

And since the other van can hold six more people,

2x + x + 6

And 57 people are transported:

3x + 6 = 57

We can then solve.

3x = 57 - 6

3x = 51

x = 17

So since we now know a small can hold 17 people, and we know that the larger van has 6 more seats, we can just say

17 + 6 = 23

So the large van has 23 seats.
5 0
3 years ago
Please help, I don’t get this
koban [17]

Answer:

3

5

12

30

50

the answers in order I believe I hope so

6 0
2 years ago
EXAMPLE 1 (a) Find the derivative of r(t) = (2 + t3)i + te−tj + sin(6t)k. (b) Find the unit tangent vector at the point t = 0. S
Tatiana [17]

The correct question is:

(a) Find the derivative of r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(b) Find the unit tangent vector at the point t = 0.

Answer:

The derivative of r(t) is 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is (j/2 + 3k)

Step-by-step explanation:

Given

r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(a) To find the derivative of r(t), we differentiate r(t) with respect to t.

So, the derivative

r'(t) = 3t²i +[e^(-t) - te^(-t)]j + 6cos(6t)k

= 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is obtained using the formula r'(0)/|r(0)|. r(0) is the value of r'(t) at t = 0, and |r(0)| is the modulus of r(0).

Now,

r'(0) = 3t²i + (1 - t)e^(-t)j + 6cos(6t)k; at t = 0

= 3(0)²i + (1 - 0)e^(0)j + 6cos(0)k

= j + 6k (Because cos(0) = 1)

r'(0) = j + 6k

r(0) = (2 + t³)i + te^(−t)j + sin(6t)k; at t = 0

= (2 + 0³)i + (0)e^(0)j + sin(0)k

= 2i (Because sin(0) = 0)

r(0) = 2i

Note: Suppose A = xi +yj +zk

|A| = √(x² + y² + z²).

So |r(0)| = √(2²) = 2

And finally, we can obtain the unit tangent vector

r'(0)/|r(0)| = (j + 6k)/2

= j/2 + 3k

8 0
3 years ago
What is the appropriate metric unit for the mass of concrete in a section of sidewalk
photoshop1234 [79]
I believe it should be Milligrams.
6 0
3 years ago
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