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katen-ka-za [31]
3 years ago
14

How will adding the value 90 affect the mean and median of the data set 1, 5, 5, 6, 9, 10?

Mathematics
2 answers:
7nadin3 [17]3 years ago
8 0
B I think is B is the answer
Soloha48 [4]3 years ago
6 0
I believe the answer is B for this question
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Since in 1990 there are 28%, we need to figure out when it gets to 31%. In addition, since it increases by 0.6% every year, we can say that 0.6x+28 (since 28 is the base value) is the percentage of babies born in wedlock every year. Therefore, to get 0.6x+28=31, we subtract 28 from both sides to get 0.6x=3
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Cylinders A and B are similar solids. The base of cylinder A has a circumference of 47 units. The base of cylinder B has an
fiasKO [112]
<h3><u>Question:</u></h3>

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.

The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

<h3><u>Answer:</u></h3>

Dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

<h3><u>Solution:</u></h3>

Cylinders A and B are similar solids.

The base of cylinder A has a circumference of 4 \pi units

The base of cylinder B has an area of 9 \pi units

Let "x" be the required factor

From given question,

Dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B

Therefore, we can say,

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }

<h3><u>Cylinder A:</u></h3>

The circumference of base of cylinder (circle ) is given as:

C = 2 \pi r

Where "r" is the radius of circle

Given that  base of cylinder A has a circumference of 4 \pi units

Therefore,

4 \pi = 2 \pi r\\\\r = 2

Thus the dimension of cylinder A is radius = 2 units

<h3><u>Cylinder B:</u></h3>

The area of base of cylinder (circle) is given as:

A = \pi r^2

Given that,  the base of cylinder B has an area of 9 \pi units

Therefore,

\pi r^2 = 9 \pi\\\\r^2 = 9\\\\r = 3

Thus the dimension of cylinder B is radius = 3 units

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }\\\\2 \times x = 3\\\\x = \frac{3}{2}

Thus dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

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Step-by-step explanation:

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