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madreJ [45]
4 years ago
9

Suppose the population of a town is 2,700 and is growing 4% each year.

Mathematics
2 answers:
Papessa [141]4 years ago
6 0

Answer:

a. y=2,700(1.04)^x

b. 4,322.

Step-by-step explanation:

a. We have been given that the population of a town is 2,700 and is growing 4% each year.

We can see that population of town is increasing exponentially. Since an exponential function is in form: y=a*b^x, where,

a = Initial value.

b= For growth b is in form (1+r), where r is rate in decimal form.

y=a*(1+r)^x

Let us convert our given rate in decimal form.

4\%=\frac{4}{100}=0.04

Upon substituting a=2,700 and r=0.04 we will get,

y=2,700(1+0.04)^x

y=2,700(1.04)^x

Therefore, the equation y=2,700(1.04)^x models the population growth.

b. To find the population after 12 years we will substitute x=12 in our population growth model.

y=2,700(1.04)^12

y=2,700*1.6010322185676808

y=4,322.78699013273816\approx 4,322

Therefore, the population after 12 years will be 4,322.


8_murik_8 [283]4 years ago
3 0
Part A
Y (x)=2700 (1+0.04)^x
Y (x)=2700 (1.04)^x
where x is the number of years

Part B
Y (12)=2,700×(1.04)^(12)=4,322.78
Round your answer to get 4323
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A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
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The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

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P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

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The straight line P has the equation y= 2x-5
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Answer:

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aksik [14]
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So he should have to work 12 hours at the restaurant. Hope this helps and sorry if it’s wrong!
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