All categories

3 years ago

Gavyn was thinking of a number. Gavyn doubles it, then adds 14 to get an answer of 17.2. What was the original number?

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

6 0

Answer:

Original number we'll call "x".

2x + 14 = 17.2

x = 1.6

Step-by-step explanation:

You might be interested in

There is same number of pennies, nickels, and dimes in a wallet. Together they make $1.28. How many coins are there in the walle

Anarel [89]

A = amount

.01a + .05a + .1a = 1.28
Combine like terms.
.16a = 1.28
Divide both sides by .16.
a = 8

8 * 3 = 24

There are 24 coins in the wallet.

7 0

3 years ago

Read 2 more answers

The temperature in Minneapolis, Minnesota, at 4 P.M. was 15°F. By midnight, the temperature had deceased by 18°. What was the te

Sholpan [36]

Answer:

23F

Step-by-step explanation:

3 0

3 years ago

A sports magazine conducted a survey to find out the size of the viewership for three different sports in a state. The survey wa

ratelena [41]

Answer:

Step-by-step explanation:

This was a bias, because in the location, there must have been a greater concentration of basketball fans than fans of any other sport.

Hope this helped.

3 0

3 years ago

Read 2 more answers

)) Ms. Terry runs the school cafeteria. In October, she had to order 15 cases of chocolate

Anna11 [10]

Answer:

I think number 2 is the answer, but 4 could be the answer.

7 0

2 years ago

Read 2 more answers

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

3 years ago