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2 years ago

Whats the surface area of A cube with the length of 5cm

Mathematics

1 answer:

melamori03 [73]2 years ago

5 0

Answer:

30 cm sq

Step-by-step explanation:

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Please help me i need to know what angle "t" is

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The angle is 90° degrees.

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3 years ago

The average distance between the Earth and the Moon is 384 400 km.<br> Express it in standard form.

ycow [4]

Answer:

$3.84\times10^8\ m$

Step-by-step explanation:

It is given that,

The average distance between the Earth and the Moon is 384 400 km.

We need to express in in standard form.

1 km = 1000 m

It means,

384400 km = 384400000 km

= $3.84\times10^8\ m$

Hence, the average distance between the Earth and the Moon is $3.84\times10^8\ m$ .

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3 years ago

A television at Walmart cost $1,538 and $1,923 at Target. With taxes, what would you actually pay at each store. Walmart sales t

mamaluj [8]

Answer:

walmart:1645.66 target:2096.07

Step-by-step explanation:

walmart:1538/100 × 107= 1645.66

target:1923/100 × 109= 2096.07

i think this is the ans but im not very sure

8 0

3 years ago

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

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3 years ago

What do two equivalent expressions always have in common

igomit [66]

Both have the same when simplified to its lowest point in the expression

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3 years ago