You have written exactly the same number twice, so neither of them is bigger.
        
             
        
        
        
81 a² - 25  is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)
 is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)
Step-by-step explanation:
The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs
- a² - b² is a difference of two squares
- a² - b² = (a + b)(a - b)
∵ The binomial is 81 a² - 25  
 
∵  = 9
 = 9
∵  = a
 = a
∴ 
∵  = 5
 = 5
∵  = z³
 = z³
∴ 
- The two terms have square root
∵ The sign between them is (-)
∴ 81 a² - 25  is a difference of two squares
  is a difference of two squares
∵ Its factorization is two identical brackets with different 
    middle signs
∵ 81 a² = 9a × 9a
∵ 25  = 5z³ × 5z³
 = 5z³ × 5z³
- The terms of the two brackets are 9a and 5z³
∴ 81 a² - 25  = (9a + 5z³)(9a - 5z³)
 = (9a + 5z³)(9a - 5z³)
81 a² - 25  is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)
 is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)
Learn more:
You can learn more about the difference of two squares in brainly.com/question/1414397
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The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
<h3>
</h3><h3>
Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
Learn more about inequalities:
brainly.com/question/24372553
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