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3 years ago

Domain and range of graphs

Mathematics

1 answer:

White raven [17]3 years ago

4 0

Answer:the domain is every “x” coordinate and the range is the “y” coordinate

Step-by-step explanation:

If you have to tell whether it’s a function or not, all of the x values in the domain will be different for a function, and 2 or more of the same x value won’t be a function

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Which rational number is greater? <br> —<br> 0.76 or 0.76? And why?

sertanlavr [38]

You have written exactly the same number twice, so neither of them is bigger.

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3 years ago

The perimeter of a rectangle is 96 ft. The ratio of its length to its width is 5 : 3. What are the dimensions of the rectangle?

fomenos

The answer is 30 to 18 feet

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3 years ago

Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.

aev [14]

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

a² - b² is a difference of two squares
a² - b² = (a + b)(a - b)

∵ The binomial is 81 a² - 25 $z^{6}$

∵ $\sqrt{81}$ = 9

∵ $\sqrt{a^{2} }$ = a

∴ $\sqrt{81a^{2}}=9a$

∵ $\sqrt{25}$ = 5

∵ $\sqrt{z^{6}}$ = z³

∴ $\sqrt{25z^{6}}=5z^{3}$

- The two terms have square root

∵ The sign between them is (-)

∴ 81 a² - 25 $z^{6}$ is a difference of two squares

∵ Its factorization is two identical brackets with different

middle signs

∵ 81 a² = 9a × 9a

∵ 25 $z^{6}$ = 5z³ × 5z³

- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 $z^{6}$ = (9a + 5z³)(9a - 5z³)

81 a² - 25 $z^{6}$ is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

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3 years ago

At 8:00 a.m. the temperature outside in Juneau, Alaska was -16.5 . By noon the temperature had increased by 15.25 . What is the

adelina 88 [10]

It would be -1.25 degrees at noon.

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3 years ago

Select all the correct answers. Which two inequalities can be used to find the solution to this absolute value inequality? 3|x +

ziro4ka [17]

The absolute value inequality can be decomposed into two simpler ones.

x < 0

x > -8

<h3></h3><h3>Which two inequalities can be used?</h3>

Here we start with the inequality:

3|x + 4| - 5 < 7

First we need to isolate the absolute value part:

3|x + 4| < 7 + 5

|x + 4| < (7 + 5)/3

|x + 4| < 12/3

|x + 4| < 4

The absolute value inequality can now be decomposed into two simpler ones:

x + 4 < 4

x + 4 > - 4

Solving both of these we get:

x < 4 - 4

x > -4 - 4

x < 0

x > -8

These are the two inequalities.

Learn more about inequalities:

brainly.com/question/24372553

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6 0

1 year ago