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vaieri [72.5K]
3 years ago
7

H(a)= a² + 4 g(a)= a + 3 Find (h – g)(a + 2)

Mathematics
1 answer:
frutty [35]3 years ago
6 0

Answer:

-5a-2

Step-by-step explanation:

pulg in the numbers ins h and g

a^2+4−(a+3)(a+2)

Distribute:

=a2+4+−a2+−5a+−6

Combine Like Terms:

=a2+4+−a2+−5a+−6

=(a2+−a2)+(−5a)+(4+−6)

=−5a+−2

Answer:

=−5a−2

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4 years ago
Let f be defined by the function f(x) = 1/(x^2+9)
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(a)

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\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

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\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}

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\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

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