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3 years ago

This is the second one

Mathematics

1 answer:

sladkih [1.3K]3 years ago

8 0

Angles in a 4-sided shape = 360 degrees
2x + x + 101 + 85 = 360
3x + 186 = 360
3x = 174
x = 58 degrees

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

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3 years ago

The figure is to be rotated 1/2 (180 degrees) turn about point P.

sesenic [268]

The answer is C. 8 units what you need to do is count how much from the starting point P is 4 units from A. simply double it by 2 to the new point to get 8 units.

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3 years ago

How do I do this!?! 2s+5 greater than or equal to 49

aev [14]

2s+5>= 49
Subtract 5 from both sides
2s>=44
Divide 2 on both sides
Final Answer: s>=22

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3 years ago

If b = 3, then b ^-2 is equivalent to 9 09 -6 01

Anni [7]

Answer:

1/9 = 0.11111111 ( infinite )

Step-by-step explanation:

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3 years ago

PLZ HELP

maria [59]

Answer:

Step-by-step explanation:

Following changes will be there when the figure is transformed by the given rules.

1). Rule for transformation has been given as,

(x, y) → (x, -y)

Reflection across x axis.

2). (x, y) → (-x, -y)

Rotation of 180° about the origin.

3). (x, y) → (x - 4, y)

Shifted 4 units left horizontally.

4). (x, y) → (x, y + 3)

Shifted vertically up by 3 units

5). (x, y) → (x - 1, y + 4)

Shifted 1 units left horizontally and 4 units up vertically.

6). (x, y) → (4x, 4y)

Dilated by 4 units.

5 0

3 years ago