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lara31 [8.8K]
2 years ago
15

CO

Mathematics
1 answer:
kramer2 years ago
7 0
The third one Hope this helps ur welcome
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The sum of two numbers is negative fifteen, and one number is five less than the other. Using the variables m and n to represent
Likurg_2 [28]

We need to use the variables m and n to represent both numbers.

Their sum must equal -15. Therefore, we can write the next equation:

m + n = -15

If one number is five less than the other, we need to choose one variable and then we can write it in terms of the other variable. Then:

n = m-5

To find the value for each number, we can replace the n equation on the first equation:

m + n = -15

m + (m-5)= -15

Then:

m + m - 5 = -15

2m -5 = -15

Solve the equation for m:

Add both sides 5 units:

2m - 5 +5 = -15+5

2m = -10

Divide both sides by 2:

2m/2 = -10/2

m = -5

Finally, replace the m value on the first equation:

m + n = -15

-5 + n = -15

Then, solve the equation for n:

Add both sides by 5:

-5+5 + n = -15 +5

n = -10

Hence, both numbers are m=-5 and n= -10.

The equations separated by a comma are m + n = -15,n = m-5.

The numbers separated by a comma are -5,-10.

6 0
1 year ago
How to find variables of these #2 & #3
Lubov Fominskaja [6]
So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles  like  \bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}

now.. for 3) will be the second picture below


\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}

8 0
3 years ago
1. WILL MARK BRAINLIEST!!! HELP!​
MatroZZZ [7]

Answer:

\frac{7}{x+7}

Step-by-step explanation:

<u>Step 1:  Pull a 7 from the top</u>

<u />\frac{7x + 42}{x^2 + 13x + 42}

\frac{7(x + 6)}{x^2 + 13x + 42}

<u>Step 2:  Factor the bottom</u>

<u />\frac{7(x + 6)}{(x + 7)(x + 6)}

<u>Step 3:  Cancel the top (x+6) and the bottom (x+6)</u>

<u />\frac{7}{x+7}

Answer:  \frac{7}{x+7}

6 0
3 years ago
What is the answer for <br> -16+x=-15
Sladkaya [172]

Answer:

x=1

Step-by-step explanation:

-16+x=-15

-16+x+16=-15+16   Add the terms to both sides of the equation.

After that you simplify.

5 0
3 years ago
Pls help meeeeeeee with this
hammer [34]
:):(:(:):)(:(:$:):(:(:(:):)3():):);;
4 0
3 years ago
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