<u>T</u><u>h</u><u>e</u><u> </u><u>s</u><u>t</u><u>a</u><u>t</u><u>e</u><u>m</u><u>e</u><u>n</u><u>t</u><u>s</u><u> </u><u>t</u><u>r</u><u>u</u><u>e</u><u> </u><u>f</u><u>o</u><u>r</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>g</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>f</u><u>u</u><u>n</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>r</u><u>e</u><u>:</u>
I tried them all and these two were correct, their solutions are as follows:
= f(x) = 1/2x + 3/2
= f(0) = 1/2 × 0 + 3/2
= f(0) = 0 + 3/2
= f(0) = 3/2
= f(x) = 1/2x + 3/2
= f(4) = 1/2 × 4 + 3/2
= f(4) = 2 + 3/2
= f(4) = 4+3/2
= f(4) = 7/2
So, that's how these two are correct.
The paper clip's length, as shown in the picture, is closest to C. 2 inches.
I hope this helps :)
Decreasing then increasing, y goes down then y goes back up
Answer: 168
Step-by-step explanation: 70/5=14. 14x7=98. 70+98=168.
Answer:
11 of 20p, 22 of 10p and 33 of 5p
Step-by-step explanation:
Eva has 20p, 10p and 5p coins, total of £6.05 = 605p
Let 20p=x, 10p=y, 5p=z
<u>Then</u>:
- 20x + 10y + 5z = 605
- y : x = 2 : 1 ⇒ x= y/2
- y : z = 2 : 3 ⇒ z= 3y/2
<u>Rewriting the first equation considering next two:</u>
- 10y + 10y + 7.5y = 605
- 27.5y = 605
- y= 605/27.5
- y= 22
- x= y/2 = 22/2 = 11
- z = 3y/2 = 3*11 = 33
<u>Answer:</u> 11 of 20p coins, 22 of 10p coins and 33 of 5p coins