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dlinn [17]
3 years ago
7

Suppose that Y has a gamma distribution with parameters α and β. a If a is any positive or negative value such that α + a > 0

, show that E(Ya ) = βa(α + a) (α) . b Why did your answer in part (a) require that α + a > 0? c Show that, with a = 1, the result in part (a) gives E(Y ) = αβ. d Use the result in part (a) to give an expression for E( √Y ). What do you need to assume about α? e Use the result in part (a) to give an expression for E(1/Y ), E(1/ √Y ), and E(1/Y 2). What do you need to assume about α in each case?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

2nd option

Step-by-step explanation:

makes most sense

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The first step is the trickery (and quite frankly, hardest to explain) part. You need to multiply one equation by a number that will create one variable to be the negative version of the other...(Confusing, right? Don't worry, I'll show you)

We are going to solve for X first.

We will multiply the second equation by -3
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Now simplify:
5x+3y= -9
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Now combine the two equations (add them together)
11x= -33
Divide by 11
X=-3

Now plug X in to one of the first equations:
5(-3)+3y= -9
-15+3y =-9
3Y= 6
Y= 2


So your final answer is:
x= -3
Y= 2

Hope this helps!
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Step-by-step explanation:

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