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dlinn [17]
3 years ago
7

Suppose that Y has a gamma distribution with parameters α and β. a If a is any positive or negative value such that α + a > 0

, show that E(Ya ) = βa(α + a) (α) . b Why did your answer in part (a) require that α + a > 0? c Show that, with a = 1, the result in part (a) gives E(Y ) = αβ. d Use the result in part (a) to give an expression for E( √Y ). What do you need to assume about α? e Use the result in part (a) to give an expression for E(1/Y ), E(1/ √Y ), and E(1/Y 2). What do you need to assume about α in each case?
Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

2nd option

Step-by-step explanation:

makes most sense

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Answer:

A. y=-\dfrac{8}{7}x-\dfrac{18}{7}

Step-by-step explanation:

Let y=mx+b be the equation of the perpendicular line.

Two perpendicular lines have slopes with product equal to -1. The slope of the given line is \frac{7}{8} Hence,

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This line passes through the point (-4,2), so its coordinates satisfy the equation:

2=-\dfrac{8}{7}\cdot (-4)+b\\ \\b=2-\dfrac{32}{7}=-\dfrac{18}{7}

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Read 2 more answers
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