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abruzzese [7]
3 years ago
11

A rectangle on the coordinate plane has vertices (-3,

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0

Answer:

hope this helps.

Step-by-step explanation:

Westkost [7]3 years ago
5 0

Answer:

the answer is 5x4

Step-by-step explanation:

hope this helps :)

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Given that (x,y) = (5,15) find tan Ø. <br><br> A. 3 <br> B. 1/3 <br> C. 5 <br> D. 1/5
lesantik [10]
This value is in the positive quadrant meaning that all values remain positive. To answer this problem you must have an understanding of trig ratios being that tangent is opposite/adjacent. When you plot the points and draw a triangle using the origin of the point, you find that the adjacent value is 5 and opposite value is 15
7 0
3 years ago
Urgent please ans this​
Rama09 [41]

Answer:

x=6

Step-by-step explanation:

Remember, the formula for area is the length times the width. So, if we know the width is 3, and we know the total area is 24, all we need to do is divide 24 by 3 to get 8. 8 is the split up side, the one that is x + 2. To find x, simply subtract 2 from 8. 8 - 2=6.

24/3=8

8-2=6

3 0
3 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
Read 2 more answers
What is the absolute value of 19.8?
arsen [322]

Answer:

19 4/5

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Plz help!! first right answer for both gets the award<br>​
Shalnov [3]

Answer:

A:in order:24,2,12,2,3  in order:84,2,42,7,3  B:168

Step-by-step explanation:

A)divide the top number by the bottom left

B)LCM of 24 and 84

6 0
3 years ago
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