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Llana [10]
3 years ago
5

Point R on the coordinate grid below shows the location of a car in a parking lot. A second car needs to park 6 units above R to

leave room for a utility truck. What are the coordinates of the location of the second car?
Image of a coordinate grid with point R R located at negative 1, negative 3.
(3 points)

(−1, −3)
(−1, 3)
(5, −3)
(5, 3)
Mathematics
1 answer:
masya89 [10]3 years ago
7 0

Answer:

Point R is located at the point (-1,-3)

The car needs to park 6 units above point R.

When you are moving something up or down on the coordinate grid, you are affecting the y- axis. So to find the coordinates we would keep the x value and add 6 to the y value.

Coordinates of the second car

(-1, -3 +6)

(-1 , 3)

The answer to this question is B

Adding a positive to a negative is the same as subtracting.

EX:

We were adding 6 and -3

Adding 6 and -3 is the same as subtracting 3 from 6.

Either way we get the same answer.

B is your answer

Hope this helps!

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Answer:

1. 90

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4. 40

5. 80

6. 60

7. 30

8. 30

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Total for all triangles=180

Step-by-step explanation:

In all the problems, you have to solve for y.  This can be done because the three angles are supplementary  For example, in the first diagram, you have:

3y+2y+y=180

6y=180

y=30

It's fairly easy to solve from there.  Just more multiplying and subtracting.

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Each week your science teacher gives a fifteen-point quiz. Your current scores are shown in the table. What is your mean quiz sc
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Answer:

12.

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To find the mean of a group of data, you add up all of the numbers and divide the total by the amount of numbers there are. In this case, you have 15,11,10,11,14,10,15,10,and 12.

All of those numbers added together is 108.

108 divided by 9 numbers, or weeks, is 12.

The average, or mean, is 12.

8 0
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Step-by-step explanation:

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Answer:

1.0.003

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Step-by-step explanation:

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
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